i don't know the anss , sorry.
Answer:
x=?
dt=?
vi=23m/s
vf=0m/s (it stops)
d=0.25m/s^2
time =
vf=vi+d: 0=23m/s+(0.25m/s^2)t
t=92s
displacement=
vf^2=vi^2+2a(dx)
23^2=0^2+2(0.25m/s^2)x =-1058m
Explanation:
you can find time from vf = vi + a(Dt): 0 = 23 m/s + (0.25 m/s/s)t so t = 92 s and you can find the displacement from vf2 = vi2 + 2a(Dx) and find the answer in one step: 232 = 02 + 2(0.25 m/s/s)x so x = -1058 m
I believe I seen on google if you go to Mather
Answer:
option B) is correct
Explanation:
perception distance is the distance traveled by the vehicle when the driver perceive the hazard situation.
reaction distance is the distance traveled by the vehicle after seeing the hazard situation and reacting to it.
Braking Distance is the distance traveled by the vehicle after applying the brake.
so, the sum of Perception Distance + Reaction Distance + Braking Distance is called the total stopping distance
hence option B) is correct .
I suppose it's C. All the other answers are everything but accurate to me
