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Aleks [24]
3 years ago
11

PLEASE HELP!! ITS URGENT!!!​

Physics
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

F = 800 [N]

Explanation:

To be able to calculate this problem we must use the principle of momentum before and after the impact of the hammer.

We must summarize that after the impact the hammer does not move, therefore its speed is zero. In this way, we can propose the following equation.

ΣPbefore = ΣPafter

(m_{1}*v_{1}) - F*t = (m_{1}*v_{2})

where:

m₁ = mass of the hammer = 0.15 [m/s]

v₁ = velocity of the hammer = 8 [m/s]

F = force [N] (units of Newtons)

t = time = 0.0015 [s]

v₂ = velocity of the hammer after the impact = 0

(0.15*8)-(F*0.0015) = (0.15*0)\\F*0.0015 = 0.15*8\\F = 1.2/(0.0015)\\F = 800 [N]

Note: The force is taken as negative since it is exerted by the nail on the hammer and this force is directed in the opposite direction to the movement of the hammer.

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Answer:

Explanation:

To detrmine the time interval at which the balls are in contact.

<u>Given information</u>

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Expression for the effective spring constant ball is shown below.

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Therefore, the velocity of cart B after the collision is 1.29 m/s.

I hope it helps you!  

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