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drek231 [11]
3 years ago
10

A physical property that describes how something feels Is called?

Physics
1 answer:
zubka84 [21]3 years ago
7 0
It's called texture, meaning how something feels.
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Block A of mass M is on a horizontal surface of negligible friction. An identical block B is attached to block A by a light stri
miv72 [106K]

Answer:

T’= 4/3 T  

The new tension is 4/3 = 1.33 of the previous tension the answer e

Explanation:

For this problem let's use Newton's second law applied to each body

Body A

X axis

      T = m_A a

Axis y

     N- W_A = 0

Body B

Vertical axis

     W_B - T = m_B a

In the reference system we have selected the direction to the right as positive, therefore the downward movement is also positive. The acceleration of the two bodies must be the same so that the rope cannot tension

We write the equations

    T = m_A a

    W_B –T = M_B a

We solve this system of equations

     m_B g = (m_A + m_B) a

    a = m_B / (m_A + m_B) g

In this initial case

     m_A = M

     m_B = M

     a = M / (1 + 1) M g

     a = ½ g

Let's find the tension

    T = m_A a

    T = M ½ g

    T = ½ M g

Now we change the mass of the second block

    m_B = 2M

    a = 2M / (1 + 2) M g

    a = 2/3 g

We seek tension for this case

    T’= m_A a

    T’= M 2/3 g

   

Let's look for the relationship between the tensions of the two cases

   T’/ T = 2/3 M g / (½ M g)

   T’/ T = 4/3

   T’= 4/3 T

The new tension is 4/3 = 1.33 of the previous tension the answer  e

4 0
3 years ago
Which object will have the most potential energy?
Svetradugi [14.3K]

Answer:  the most potential energy ==  5 kg book, 2 m from the ground= 98 Joules

Explanation:

potential energy = m g h

m = mass

g = acceleration due gravity  = 9.8 m/s²

h = distance above  ground

1.  Pe₁ = 1 kg x 2 m x g  = 2 g

2. Pe₂ = 5 kg x 2 m x g = 10 g = 10 kg m x 9,8 m/s² = 98 Joules

3. Pe₃ = 1 kg x 0,5 m x g = 0,5 g

4. Pe₄ = 5 kg x 0.5 m x g = 2,5 g  

10 > 2,5 > 2 >0,5

5 0
3 years ago
If your heart is beating at 76. 0 beats per minute, what is the frequency of your heart's oscillations in hertz?
nikitadnepr [17]

If the heart is beating at 76. 0 beats per minute, the Frequency of heart's oscillations in hertz is 1.25 Hertz.

The Frequency is defined as the number of oscillations completed in 1s.

Our heart beats continuously giving rise to the frequency of the heart.

Measuring frequency would be possible if we measure the time in seconds.

75 beats per minute means that 75 beats occur in 60s.

Frequency = Number of beats / Total time taken

Frequency = 75 / 60

Frequency = 1.25 Hz

Hence, number of beats per second is 1.25 Beats.

Beats per second or Cycles per second is same as the frequency of oscillation called as Hertz (Hz)

Hence, frequency of the heart oscillation is 1.25 Hertz (Hz).

Learn more about Frequency here, brainly.com/question/14316711

#SPJ4

5 0
1 year ago
Suppose that a rectangular toroid has 1,500 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i
V125BC [204]

Answer:

Current in the toroid will be I=17.32\times 10^{-3}A

Explanation:

We have given number of winding in rectangular toroid N = 1500

Self inductance of toroid L = 0.06 H

Magnetic energy stored in toroid E=9\times 10^{-16}J

We have to find the current in the toroid

Magnetic energy stored is equal to E=\frac{1}{2}Li^2

9\times 10^{-6}=\frac{1}{2}\times 0.06\times I^2

I=17.32\times 10^{-3}A

So current in the toroid will be I=17.32\times 10^{-3}A

5 0
3 years ago
Increasing the # of pulleys increases the _______ but decreases the amount of ______ applied
Maksim231197 [3]

Distance, Force

<u>Explanation:</u>

1)  Increasing the load will add to the friction on the bearings of the pulleys, thus reducing the efficiency of the system.  The ideal mechanical advantage won't change since the ideal mechanical advantage ignores friction.

2)  Increasing the number of pulleys will increase the ideal mechanical advantage, but because of friction it will decrease the efficiency.  The more pulleys that are turning, the more friction there is, and the less efficient the system will be.

3)  Work = force x distance, and what machines do is alter the amount of force you can apply while at the same time reducing the distance moved by the same factor.  For instance, a jack multiplies the force you apply by a factor of 100, when you push down on the handle of the jack 100 cm, the car will only go up 1 cm.  So the force x distance is the same 100 x force x 1/100 x distance.

8 0
3 years ago
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