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Oksana_A [137]
3 years ago
9

A 625 kg sailboat moves with a momentum of 13,200 kg•m/s what is the velocity of the sailboat

Physics
1 answer:
Katyanochek1 [597]3 years ago
7 0
Momentum is equal to the Mass*Velocity
Mass=625 kg
Velocity=? m/s
Momentum=13,200 kg*m/s

Momentum is p
Mass is m
Velocity is v
p=mv

13,200=625v
divide both sides by 625

v=21.12 m/s

If you have any questions, feel free to ask. Hope this helps
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Answer:

Explanation:

Rotate it slowly to establish whether the spot moves. If it is broken, it will stay as it is. By rotating it the electrons' path to the centre of the screen will be tilted to another position by any external disturbing field.

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3 years ago
What is the energy per photon absorbed during the transition from n = 2 to n = 3 in the hydrogen atom?
adelina 88 [10]

Answer : The energy of one photon of hydrogen atom is, 3.03\times 10^{-19}J

Explanation :

First we have to calculate the wavelength of hydrogen atom.

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 10973731.6 m⁻¹

n_f = Higher energy level = 3

n_i= Lower energy level = 2

Putting the values, in above equation, we get:

\frac{1}{\lambda}=(10973731.6)\left(\frac{1}{2^2}-\frac{1}{3^2} \right )

\lambda=6.56\times 10^{-7}m

Now we have to calculate the energy.

E=\frac{hc}{\lambda}

where,

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = 6.56\times 10^{-7}m

Putting the values, in this formula, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{6.56\times 10^{-7}m}

E=3.03\times 10^{-19}J

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3 0
3 years ago
Two carts have a compressed spring between them and are initially at rest. One of the carts has total mass, including its conten
ladessa [460]

Answer:

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now plug in all data into above equation

5(v) + 3(3)

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so correct answer is

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3 0
3 years ago
The mean time between collisions for electrons in room temperature copper is 2.5 x 10-14 s. What is the electron current in a 2
Darya [45]

Answer:

1.87 A

Explanation:

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A = (0.25) πd²

A = (0.25) (3.14) (2 x 10⁻³)²

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3 years ago
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Korvikt [17]

Answer:

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3 0
3 years ago
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