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3 years ago

A 625 kg sailboat moves with a momentum of 13,200 kg•m/s what is the velocity of the sailboat

1 answer:

7 0

Momentum is equal to the Mass*Velocity
Mass=625 kg
Velocity=? m/s
Momentum=13,200 kg*m/s

Momentum is p
Mass is m
Velocity is v
p=mv

13,200=625v
divide both sides by 625

v=21.12 m/s

If you have any questions, feel free to ask. Hope this helps

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A -5.0 μC charge experiences a 11 i^ N electric force in a certain electric field. [Recall that i^ is a unit vector in the x-dir

Pachacha [2.7K]

Answer:

$\vec{F}= -3.52\times 10^{-13}\hat{i}\ N$

Explanation:

given,

charge = -5.0 μC

Electric force, F = 11 i^ N

force would a proton experience = ?

we know

$\vec{F} = q \vec{E}$

$11\hat{i} = -5 \times 10^{-6} \vec{E}$

$\vec{E} =-2.2 \times 10^{6}\hat{i}$

we know charge of proton is equal to 1.6 x 10⁻¹⁹ C

using formula

$\vec{F} = q \vec{E}$

$\vec{F}= 1.6 \times 10^{-19}\times -2.2 \times 10^{6}\hat{i}$

$\vec{F}= -3.52\times 10^{-13}\hat{i}\ N$

Force experienced by the photon in the same field is equal to $\vec{F}= -3.52\times 10^{-13}\hat{i}\ N$

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3 years ago

Which statement correctly describes these electric field lines

JulijaS [17]

Answer:

Explanation:

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3 years ago

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What are some evidences of early peoples concern for teeth

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Replacement teeth were made even back then out of primitive materials, and pig hair was used like floss

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4 years ago

A soccer ball is released from rest at the top of a grassy incline. After 6.2 seconds, the ball travels 47 meters. One second la

alexandr1967 [171]

Answer:

(a) a = 2.44 m/s²

(b) s = 63.24 m

Explanation:

(a)

We will use the second equation of motion here:

$s = v_it+\frac{1}{2}at^2$

where,

s = distance covered = 47 m

vi = initial speed = 0 m/s

t = time taken = 6.2 s

a = acceleration = ?

Therefore,

$47\ m = (0\ m/s)(6.2\ s)+\frac{1}{2}a(6.2\ s)^2\\\\a = \frac{2(47\ m)}{(6.2\ s)^2}$

a = 2.44 m/s²

(b)

Now, we will again use the second equation of motion for the complete length of the inclined plane:

$s = v_it+\frac{1}{2}at^2$

where,

s = distance covered = ?

vi = initial speed = 0 m/s

t = time taken = 7.2 s

a = acceleration = 2.44 m/s²

Therefore,

$s = (0\ m/s)(6.2\ s)+\frac{1}{2}(2.44\ m/s^2)(7.2\ s)^2\\\\$

s = 63.24 m

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3 years ago

A small, closed chamber of gas is heated. When the gas in the chamber expands,it does 5 J of work on a piston. The gas has an in

Anestetic [448]

Given:

Work done, W = 5 J

Initial energy = 8J

Final energy = 30J

Let's determine if the work done have a positive or nrgative value.

Appy the equation for the first lae of thermodynamics:

$\Delta U=Q-W$

Where:

U is the change in internal energy

Q is the added heat

W is the work done

To find the work done here, we have:

Rewrite the formula for W

$W=Q-\Delta U$

Where:

ΔU = 30J - 8J = 22J

Q = 5J

Thus, we have:

$\begin{gathered} W=5J-22J \\ \\ W=-17J \end{gathered}$

Therefore, the work done here is -17J.

This means the work done in this scenario has a negative value.

ANSWER:

The work done in this scenario has a negative value

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2 years ago