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Yuri [45]
3 years ago
5

A piano tuner is tuning a piano when he discovers that the G above middle C is vibrating with a higher frequency than his G tuni

ng fork, which vibrates at 392.0 Hz. He plays the piano key and tuning fork at the same time and hears a beat frequency of 2.0 Hz.
a. What is the frequency of the G on Ms. Carlton's piano?
b. If it had been a lower frequency, creating a beat frequency of 4.0 Hz, what would it have been?
Physics
1 answer:
kotegsom [21]3 years ago
6 0

Answer:

Tuning a piano is the process of adjusting the tension of its strings, thereby altering their pitch, or frequency of vibration, by slightly turning the tuning pins to which they're attached, so that each string sounds pleasingly in harmony with every other string.

<h2>Hopefully u will satisfy with my answer of ur question..!!</h2>

<h2>Have a nice day ahead dear..!!</h2>
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Answer:

57 N

Explanation:

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F_net = √(51.66² + 24.09²)

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EleoNora [17]

Answer:

The tank is losing 4.976*10^{-4}  m^3/s

v_g = 19.81 \ m/s

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According to the Bernoulli’s equation:

P_1 + 1 \frac{1}{2} \rho v_1^2 + \rho gh_1 = P_2 +  \frac{1}{2}  \rho v_2^2 + \rho gh_2

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v_2 = \sqrt{[2*9.81*(20 - 15)]

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b)

How fast is the water from the hole moving just as it reaches the ground?

In order to determine that; we use the relation of the velocity from the equation of motion which says:

v² = u² + 2gh ₂

v² = 9.9² + 2×9.81×15

v² = 392.31

The velocity of how fast the water from the hole is moving just as it reaches the ground is : v_g = \sqrt{392.31}

v_g = 19.81 \ m/s

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Answer:

The frequency of the wave is 5.0Hz

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