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Papessa [141]
3 years ago
14

The chemical bonding in sodium phosphate, Na3PO4, is classified as:

Chemistry
2 answers:
Ket [755]3 years ago
8 0
Between these, the bond is called an ionic bond. An ionic bond is when the electrons are transferred between the atoms, giving them a charge. 
fiasKO [112]3 years ago
7 0
<span>Ionic bonding between sodium and phosphate ions.</span>
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Which set of changes does not involve breaking or forming chemilcal bonds
sineoko [7]
<h2><u>Answer:</u></h2>

It wasn't an adjustment in the condition of issue on the grounds that the vitality in the can did not change. Additionally, since this was a physical change, the atoms in the can are as yet similar particles. No synthetic bonds were made or broken.  You added enough vitality to make a stage change from strong to fluid.  

The main changes recorded which don't include framing or breaking substance bonds would bubble and liquefying. Bubbling and liquefying are physical changes as opposed to synthetic changes, so no new items are shaped.

6 0
3 years ago
What is the molarity of a solution that contains 0.220 moles KOH in 0.350 L of solution?
Lera25 [3.4K]

Answer:

0.628 M.

Explanation:

In order to solve this problem we need to keep in mind the<em> definition of molarity</em>:

  • Molarity = moles / liters

We are given both the <em>number of moles and the volume of solution</em>, meaning we can now proceed to <u>calculate the molarity</u>:

  • Molarity = 0.220 mol / 0.350 L
  • Molarity = 0.628 M
5 0
3 years ago
Calculate the percentage of water of crystallisation in MgSO⁴ 7H²O
Bas_tet [7]

Answer:

Formula of EPSOM salt = MgSO4.7H2O

molecular mass of MgSO4.7H2O = atomic mass of Mg + atomic mass of S + 4 × atomic mass of O + 7 { 2 × atomic mass of H + atomic mass of O }

= 24 + 32 + 4× 16 + 7{ 2 × 1 + 16 } g/mol

= (24 + 32 + 64+ 126 ) g/mol

= 246 g/mol

molecular mass of total water = 7 × ( 2× atomic mass of H + atomic mass of O )

= 7 × 18 = 126 g/mol

now ,

% mass of H2O in EPSOM salt = {total molar mass of H2O/molar mass of Epsom salts }× 100

= {126/246 } × 100

= 12600/246

= 51.21 %

Explanation:

i have done it hope it helps

7 0
3 years ago
Read 2 more answers
Determine the number of atoms in 41.0 grams of calcium, Ca. (The mass of one mole of calcium is 40.08 g.)
Dovator [93]

Hi there!

Let me know if you have questions about my answer:

6.15 × 10²⁴

Explanation:

To find the number of atoms, divide the mass of calcium (m) by its molar mass (MM). This will give you the number of moles of calcium (n).

n = m/MM            Start with a formula

=\frac{41.0g}{40.08g/mol}             Substitute values from the question

= \frac{41.0g*1mol}{40.08g}             Simplify

= \frac{41.0mol}{40.08}                 Cancel out the units "g"

= 1.022...mol          Number of moles of calcium, with 4 significant figures

Then, multiply the number of moles of calcium (n) by Avogadro's number (N_{A}) to find the number of calcium atoms.

Number.of.Ca=n*N_{A}      Start with a formula

= 1.022mol*\frac{6.022*10^{23}Ca}{1mol}      Substitute values from the question

= \frac{1.022mol*6.022*10^{23}Ca}{1mol}           Simplify

= 1.022*(6.022*10^{23}Ca)     Cancel out the units "mol"

= 6.154*10^{24} Ca                   Multiply, leave one extra digit to help round. "4" tells you to round down.

= 6.15*10^{24} Ca                     Final answer to 3 significant figures*

*When multiplying and dividing numbers, your final answer will have the same number of significant figures as the number with the least number of significant figures in the question.

40.08 has 4 significant figures. 41.0 has 3 significant figures. So, you want 3 significant figures in your final answer.

I hope this helps!

Learn more about Avogadro's number here:

brainly.com/question/1445383

Check out another answer that uses significant figures:

brainly.com/question/3721164

7 0
2 years ago
What is the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml?
Firdavs [7]

Answer: The final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,  

M_1 = molarity of stock CuSO_4 solution = 2.5 M

V_1 = volume of stock CuSO_4solution = 5 ml  

M_1 = molarity of diluted CuSO_4 solution = ?

V_1 = volume of diluted CuSO_4 solution = 750 ml

Putting in the values we get:

2.5\times 5=M_2\times 750

M_2=0.017

Therefore the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

6 0
3 years ago
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