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3 years ago

The chemical bonding in sodium phosphate, Na3PO4, is classified as:

2 answers:

8 0

Between these, the bond is called an ionic bond. An ionic bond is when the electrons are transferred between the atoms, giving them a charge.

fiasKO [112]3 years ago

7 0

Ionic bonding between sodium and phosphate ions.

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In which type of condition is a conditions is a landslide most likely to occur

masha68 [24]

Answer:

B. In a wet, hilly area

Explanation:

We know that for a landslide to happen, there has to be a down hill slope so it can fall.

This eliminates answers C, D and E.

So we are left with A and B

Now we can look at this in a real life scenario. If you have ever walking on wet ground, you will know that is weaker than dry ground. Knowing this, we know the answer will have to be answer B.

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2 years ago

Gymnast always perform on padded mats. how does the mats protect the gymnast

dalvyx [7]

So if they fall, the padding will protect their neck or body part so they will not hit hard against the hard wooden or tile floor.

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3 years ago

Read 2 more answers

What is the ratio of molecules in: CH4 + 2O2 -> CO2 + 2H2O

nalin [4]

Answer:

1:2:1:2

Explanation:

A molecule is made up of aggregates of small particles called atoms.

CH₄ + 2O₂ → CO₂ + 2H₂O

From the reaction above we have: 1 molecule of methane CH₄ reacting with 2 molecules of oxygen gas O₂ to produce 1 molecule of carbon dioxide gas CO₂ and 2 molecules of H₂O:

CH₄ + 2O₂ → CO₂ + 2H₂O

1 : 2 : 1 : 2

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3 years ago

Que influencia tiene la temperatura en la evaporación de los liquidos

drek231 [11]

Answer:

Explanation:

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3 years ago

Cyclopentene is a cyclic hydrocarbon like the ones used in the experiment. In another bomb calorimetry experiment 0.8278 g of cy

melisa1 [442]

Answer:

Computed value is 45.3 kJ/mol whereas the accepted one is 32.6 kJ/mol which means there is a significant difference between them.

Explanation:

Hello.

In this case, for this problem we write the following equation, representing that the heat released due to the combustion of cyclopentane equals the heat gained by the calorimeter:

$Q_{cyclop}=-Q_c$

Which can be also written as:

$n_{cyclop}\Delta _cH_{cyclop}=-C_c(T_f-T_i)$

In such a way, we can compute the enthalpy of combustion of cyclopentane:

$\Delta _cH_{cyclop}=\frac{-C_c(T_f-T_i)}{n_{cyclop}} =\frac{-10.56\frac{kJ}{\°C} (22.955-19.341)\°C}{0.8278g*\frac{1mol}{70.1g} }=-3231.8kJ/mol$

Next, since the combustion of cyclopentane is:

$C_5H_1_0+\frac{15}{2} O_2\rightarrow 5CO_2+5H_2O$

And the enthalpy of combustion is computed thermochemically as:

$\Delta _cH_{cyclop}=5\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_5H_1_0}$

Since the enthalpy of formation of CO2 and H2O are -395.5 and -241.8 kJ/mol respectively, we can compute the enthalpy of formation of cyclopentane based on the previously computed enthalpy of combustion on the calorimeter part:

$\Delta _fH_{C_5H_1_0}=5\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _cH_{cyclop}\\\\\Delta _fH_{C_5H_1_0}=5*-395.5+5*-241.8-(-3231.8)\\\\\Delta _fH_{C_5H_1_0}=45.3kJ/mol$

In such a way, we see a significant difference between the computed value 45.3 kJ/mol and the accepted value 32.6 kJ/mol.

Best regards.

8 0

3 years ago