<span>Answer is: 2940 mL of
the HCL solution.</span>
c₁(HCl) = 10.0 M.
V₂(AgNO₃<span>) = ?.
c</span>₂(AgNO₃<span>) = 0.85 M.
V</span>₁(AgNO₃<span>) = 250 mL </span>÷ 1000 mL/L = 0.25 L.
<span>
c</span>₁<span> - original concentration of the solution, before it
gets diluted.
c</span>₂<span> - final concentration of the solution, after dilution.
V</span>₁<span> - volume to be diluted.
V</span>₂<span> - final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂<span>.
V</span>₂(HCl) = c₁ · V₁ ÷ c₂.
<span>
V</span>₂(HCl) = 10 M · 0.25 L ÷ 0.85 M.
<span>
V</span>₂(HCl) = 2.94 L ·
1000 mL = 2940 mL.
<h2>Greetings!</h2>
Because 1 atm is equal to 760mm Hg, you can use the following equation to find the correct atm measurement:
atm x 760
Simply plug the values given in:
0.43 x 760 = 326.8mm Hg
<h2>Hope this helps!</h2>
Answer:
here
Explanation:
0.000141 to kilowatt-hours. hope this helped
Answer: 20 mg Te-99 remains after 12 hours.
Explanation: N(t) = N(0)*(1/2)^(t/t1/2)
N(t) = (80 mg)*(0.5)^(12/6)
N(t) = 20 mg remains after 12 hours
The molar mass of salt (NaCl) is 22.99+35.45 = 58.44 g/mol. If we have 0.18 mg of salt, this is equivalent to 0.00308 mmol NaCl, or 3.1E-6 mol NaCl. By definition, 1 mole contains 6.02E23 formula units, so multiplying this by the number of moles gives the answer, which is: 1.9E18 formula units.
