1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nezavi [6.7K]
2 years ago
6

What is the mole fraction of NaOH in an aqueous solution that

Chemistry
1 answer:
astraxan [27]2 years ago
4 0

Answer:

The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

Explanation:

We are given that

Aqueous solution that contains 22.9% NaOH by mass means

22.9 g NaOH in 100 g solution.

Mass of NaOH(WB)=22.9 g

Mass of water =100-22.9=77.1

Na=23

O=16

H=1.01

Molar mass of NaOH(MB)=23+16+1.01=40.01

Number of moles =\frac{Given\;mass}{Molar\;mass}

Using the formula

Number of moles of  NaOH(n_B)=\frac{W_B}{M_B}=\frac{22.9}{40.01}

n_B=0.572moles

Molar mass of water=16+2(1.01)=18.02g

Number of moles of water(n_A)=\frac{77.1}{18.02}

n_A=4.279 moles

Now, mole fraction of NaOH

=\frac{n_B}{n_B+n_A}

=\frac{4.279}{0.572+4.279}

=0.882

Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

You might be interested in
A compound is found to contain 42.88 % carbon and 57.12 % oxygen by weight. To answer the questions, enter the elements in the o
Ipatiy [6.2K]

Answer:

The empirical formule is CO

Explanation:

Step 1: Data given

Suppose the mass of a compound is 100 grams

Suppose the compound contains:

42.88 % C = 42.88 grams C

57.12 % O = 57.12 grams O

Molar mass C = 12.01 g/mol

Molar mass O = 16.0 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles C = mass C / molar mass C

Moles C = 42.88 grams / 12.01 g/mol

Moles C = 3.57 moles

Moles O = 57.12 grams / 16.0 g/mol

Moles O = 3.57 moles

Step 3: Calculate the mol ratio

We divide by the smallest amount of moles

C: 3.57 moles / 3.57 moles = 1

O: 3.57 moles / 3.57 moles = 1

The empirical formule is CO

3 0
2 years ago
Please help. It's for chemistry
irinina [24]
What do i help with what
3 0
2 years ago
-Before we begin each flame test we will
ludmilkaskok [199]

Answer:Poop

Explanation:poop

7 0
3 years ago
A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the
horrorfan [7]

Answer : (C) Hafnium is the most likely identity of the given substance.

Solution :  Given,

Mass of given substance (m) = 46.9 g

Volume of given substance (V) = 3.5 Cm^{3}

First, find the Density of given substance.

Formula used :    

Density=\frac{\text{Mass of given substance}}{\text{Voume of given substance}}

Now,put all the values in this formula, we get

Density=\frac{46.9 g}{3.5 Cm^{3} } = 13.4 g/Cm^{3}

So, we conclude that the density of given substance (13.4 g/Cm^{3}) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/Cm^{3} respectively).

According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.

Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.

So, Hafnium is the most likely element which is the identity of the given substance.

3 0
3 years ago
Read 2 more answers
Which of the following best describes the solar radiation absorbed by and radiated from earth?
FinnZ [79.3K]

Answer:

the answer that you are looking for is d

Explanation:

4 0
2 years ago
Read 2 more answers
Other questions:
  • The [α] of pure quinine, an antimalarial drug, is −165. If a solution contains 86% quinine and 14% of its enantiomer (ee = 72%),
    12·1 answer
  • A 1.50 liter flask at a temperature of 25°C contains a mixture of 0.158 moles of methane, 0.09 moles of ethane, and 0.044 moles
    8·2 answers
  • How many liters are in one kiloliter?
    6·1 answer
  • Use the ruler to determine the length of the line measured to the correct degree of precision. 13.2 cm 13.25 cm 130 cm 132 mm
    8·2 answers
  • The decomposition of N I 3 to form N 2 and I 2 releases − 290.0 kJ of energy. The reaction can be represented as 2N I 3 (s)→ N 2
    9·1 answer
  • Consider the following reaction:
    9·1 answer
  • Of the following two gases,
    8·1 answer
  • Gasoline is made up mainly of one general class of chemical, of which octane is an example. This is the "fuel" part of gasoline.
    14·1 answer
  • (S)-3-Methylhexane undergoes radical bromination to yield optically inactive 3-bromo-3-methylhexane as the major product. Is the
    15·1 answer
  • Barium chlorate (Ba(ClO3)2) breaks down to form barium chloride and oxygen. What is the balanced equation for this reaction? Whe
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!