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Viktor [21]
3 years ago
12

Give me the right answer

Mathematics
2 answers:
olga2289 [7]3 years ago
8 0

Answer:the range is B

Step-by-step explanation:

trasher [3.6K]3 years ago
4 0

Answer:

CCCCCCC

Step-by-step explanation:

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The diameter of a circle is 9 ft. Find its area to the nearest tenth.
Drupady [299]

Step-by-step explanation:

D=9

A=pie*radius^2

=3.14*9/2*9/2

=63.58

=64

6 0
3 years ago
Read 2 more answers
Solve equation.<br> 2x-5y=20
Novay_Z [31]
If you solve for x you get:
x=(<span><span><span>5/2)</span>y</span>+<span>10
</span></span>
If you solve for y you get:
y=(<span><span><span>2/5)</span>x</span>−<span>4</span></span>
5 0
3 years ago
A car traveled 330 miles during a 5½ hour period. If the speed at which the car traveled can be represented in the equation d=rt
Alina [70]

Answer:

The car was travelling at a speed of 60 miles per hour.

Step-by-step explanation:

Given:

Distance traveled = 330 miles

Time Period = 5 \frac12\ hr

we need to find the speed of the car .

Solution:

Time Period = 5 \frac12\ hr

Now we can say that;

\frac12\ hr =0.5\ hr

So Time period = 5+0.5 =5.5\ hr

Now we know that;

Distance traveled (d) is equal to Speed (r) multiplied by Time Period (t).

framing in equation form we get;

d=rt\\\\330 =r\times 5.5

Dividing both side by 5.5 we get;

\frac{330}{5.5}=\frac{5.5r}{5.5}\\\\r = 60\ mi/hr

Hence The car was travelling at a speed of 60 miles per hour.

6 0
3 years ago
Help please!!!!<br> Solve the system by graphing
kotegsom [21]

Answer:

picture of graph is attached. lmk if ur getting these right. its been a while since I've dont this

7 0
3 years ago
In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
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