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kolezko [41]
2 years ago
15

A thin disk of mass 2.2 kg and radius 61.2 cm is suspended by a horizonal axis perpendicular to the disk through its rim. The di

sk is displaced slightly from equilibrium and released. The acceleration of gravity is 9.81 m/s2. Find the period of the subsequent simple harmonic motion. Answer in units of s.
Physics
1 answer:
Alinara [238K]2 years ago
7 0

Answer: The period of the subsequent simple harmonic motion is 1.004 sec.

Explanation:

The given data is as follows.

  Mass of disk (m) = 2.2 kg,     radius of the disk (r) = 61.2 cm,

Formula to calculate the moment of inertia around the center of mass is as follows.

          I_{cm} = \frac{1}{2}mr^{2}  

                     = \frac{1}{2} \times 2.2 kg \times (61.2)^{2}

                     = 0.412 kg m^{2}

Also,

Distance between center of mass and axis of rotation (d) = r = 0.612 m

Moment of inertia about the axis of rotation (I)

        I = I_{cm} + md^{2}

       I = 0.412 + (2.2) \times (0.612)^{2}

          = 0.339 kgm^{2}

Now, we will calculate the time period as follows.

        T = 2\pi sqrt{\frac{I}{mgd})

        T = 2 \times 3.14 sqrt{(\frac{0.339}{2.2 \times 9.8 \times 0.612}

        T = 1.435 sec

      T = 2 \times 3.14 \times 0.16

          = 1.004 sec

Thus, we can conclude that the period of the subsequent simple harmonic motion is 1.004 sec.

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The radder clocked sonic going 300 miles per hour how long will it take him to go 48.1 miles from Miami to Florida
lys-0071 [83]

Answer:

9.62 minutes 0r 0.16 of an hour

Explanation:

Speed = distance/time

300mph = 48.1 m/t

xt

300t = 48.1

÷300

t = 48.1/300

t = 0.16033333333 hr

0.16033333333 x 60 = 9.62 minutes

60 minutes in an hour

9.62/60= 0.16033333333 hr

So, around 10 minutes.

Hope this helps!

8 0
2 years ago
Suppose the odometer on our car is broken and we want to estimate the distance driven over a 30 second time interval. We take th
Natalija [7]

Let say for every 5 s of time interval the speed will remain constant

so it is given as

v(mi/h)   16    21    23    26    33    30     28

now we have to convert the speed into ft/s as it is given that 1 mi/h = 5280/3600 ft/s

so here we will have

v(ft/s)      23.5    30.8     33.73     38.13     48.4     44     41.1

now for each interval of 5 s we will have to find the distance cover for above interval of time

d = v \times t

d = (23.5 + 30.8 + 33.73 + 38.13 + 48.4 + 44 + 41.1) \times 5

d = 1298.1 ft

so here it will cover 1298.1 ft distance in 30 s interval of time

4 0
3 years ago
Read 2 more answers
you throw a ball vertically so it leaves the ground withe velocity of 3.71m/s. what is its acceleration at this point
tino4ka555 [31]

No matter what direction you throw it, or with what speed, its acceleration is immediately 9.8 m/s^2 downward as soon as you release it from your hand, and it doesn't change until the ball hits something.

4 0
3 years ago
In a single-slit diffraction experiment, the slit is 0.1mm wide and is illuminatedby monochromatic light with a wavelength of 50
dem82 [27]

Answer:

0.1 m

Explanation:

d = slit width = 0.1 mm = 0.1 x 10⁻³ m

\lambda = wavelength of monochromatic light = 500 nm = 500 x 10⁻⁹ m

D = Distance of the screen = 10 m

w = Spacing between successive minima

Spacing between successive minima is given as

w = \frac{2D\lambda }{d}

Inserting the values given

w = \frac{2(10)(500\times10^{-9}) }{0.1\times10^{-3}}

w = 0.1 m

4 0
3 years ago
A water wave of wavelength 859 cm travels a distance of 64 m in a time of 14 s. What is the period of the wave, in units of seco
swat32

Answer:

1.87 s

Explanation:

d = distance traveled by the water wave = 64 m

t = time taken to travel the distance = 14 s

v = speed of water wave

Speed of water wave is given as

v=\frac{d}{t}

v=\frac{64}{14}

v = 4.6 m/s

\lambda = wavelength of the wave = 859 cm = 8.59 m

T = period of the wave

period of the wave is given as

T = \frac{\lambda }{v}

T = \frac{8.59 }{4.6}

T = 1.87 s

8 0
3 years ago
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