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vodomira [7]
3 years ago
13

Coal can be used to generate hydrogen gas (a potential fuel) by thefollowing endothermic reaction.

Chemistry
1 answer:
Juliette [100K]3 years ago
7 0

Answer:The statements b,c,d would lead to increased formation of more hydrogen gas and statements a, e and f would  lead to unchanged hydrogen concentration

Explanation:

Lechateliers principle can be used here to determine the effect  of changes observed in the system.

Lechateliers principle states that if  any reaction at equilibrium  is subjected to change in concentration, temperature and pressure or even in reaction conditions  then the equilibrium of the reaction would shift in such a way so that it can oppose the change .

So if any disturbance is caused to a reaction  at equilibrium hence  the equilibrium of reaction would shift in such a way so that it can counter balance the change caused to the reaction.

The above reaction is following:

C(s)+H₂O(g)→CO(g)+H₂(g)

The enthalpy change  of this reaction is positive and hence the reaction is endothermic in nature.

So the given changes would lead to the following  results:

a The addition of more amount of carbon C(s) would not lead to any further formation of hydrogen because carbon is added in solid state and Hydrogen gas is in gaseous state so the equilibrium for this given reaction would only change on addition of gaseous reactants as that would only lead to change in concentration.

b Since H₂O(g) is in gaseous state and a reactant and hence the addition of  H₂O(g) that is more reactant would lead to more formation of hydrogen gas according to lechatelier principle. The equilibrium would shift in such a way so that it can decrease the concentration of added H₂O(g) hence it would form H₂(g).

c Since the above reaction is endothermic in nature hence increasing the temperature of reaction would also shift the equilibrium of reaction towards more formation of H₂(g) that is in forward direction.

d When we increase the volume of reaction mixture that is we are increasing the amount of reactants hence the reaction would shift towards more formation of hydorgen gas.

e The catalyst does not change the position of equilibrium and hence no shift in position of equilibrium would be observed.So amount of hydrogen gas formed would remain unchanged.

f The addition of inert gas would not lead to any change to the reaction and equilibrium would be unaffected. Hence the formation of hydrogen gas would remain unchanged.

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What is the mass in grams of 5.00moles of CH4?
anastassius [24]

Answer:

1. 80g

2. 1.188mole

Explanation:

1. We'll begin by obtaining the molar mass of CH4. This is illustrated below:

Molar Mass of CH4 = 12 + (4x1) = 12 + 4 = 16g/mol

Number of mole of CH4 from the question = 5 moles

Mass of CH4 =?

Mass = number of mole x molar Mass

Mass of CH4 = 5 x 16

Mass of CH4 = 80g

2. Mass of O2 from the question = 38g

Molar Mass of O2 = 16x2 = 32g/mol

Number of mole O2 =?

Number of mole = Mass /Molar Mass

Number of mole of O2 = 38/32

Number of mole of O2 = 1.188mole

6 0
3 years ago
Is anyone good at 10th grade chemistry ? If so can you help me please
Harrizon [31]

Answer:

221.7 K

Explanation:

As, PV = nRT

Hence,

6.5 (14) = 5(0.0821)T

91 = 0.4105 T

91 ÷ 0.4105 = T

221.7 = T

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Ag= [Kr] 5s^2 4d^9

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4 years ago
Please help!
adoni [48]

2. 15.65 grams of KCl is formed if 25.0 g of Potassium Chlorate, KClO3, decompose.

3. 2.17 moles of H2 gas produced when 100.0 grams of Na is added to the reaction.

4. 7.5 moles of Hydrogen, H2, are needed to react with 2.5 moles of Nitrogen, N2.

Explanation:

2. The balanced equation for the chemical reaction is:

2KClO3 ⇒ 2KCl + 3O2

Data given:

mass of KClO3 = 25 grams, atomic mass of KClO3 = 122.55 grams/mole

KCl produced =?  atomic mass of KCl = 74.55

number of moles = \frac{mass}{atomic mass of one mole}

                              = \frac{25}{122.55}

  number of moles = 0.20 moles of KCO3

2 moles of KClO3  decomposes to give 2KCl

0.21 moles of KClO3 decomposes to give x moles of KCl

\frac{2}{2} = \frac{x}{0.21}

x = 0.21 moles of KCl

mass of KCl = 0.21 x 74.55

                     = 15.65 grams of KCl is formed.

3. data given:

2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)

mass of Na added = 100 grams, atomic mass of Na = 22.98 grams/mole

moles of H2 =?

Number of moles of Na = \frac{mass}{atomic mass of one mole}

                            = \frac{100}{22.98}

         number of moles of Na = 4.35 moles

2 moles of Na gives 1 mole of H2

4.35 moles of Na will give x moles

\frac{1}{2} = \frac{x}{4.35}

2x = 4.35

x = 2.17 moles of hydroden gas is produced.

4. Data given:

the balanced chemical equation:

N2 + 3H2 → 2NH3

Number of moles of N2 2.5

from the reaction

1 mole of N2 reacts with 3 moles of H2

The molar ratio of the reactant is 1:3

so, \frac{1}{3}= \frac{2.5}{x}

x = 7.5 moles of H2 will react with 2.5 moles of N2.

7 0
3 years ago
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lianna [129]
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3 years ago
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