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3 years ago

Write an equation of the circle with center (8.-3) and radius 6

Mathematics

1 answer:

murzikaleks [220]3 years ago

7 0

Answer:

(x -8)^2 +(y +3)^2 = 36

Step-by-step explanation:

The equation of a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r2

Putting your numbers into this form gives ...

(x -8)^2 +(y +3)^2 = 36

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HELP PLEASE!

Archy [21]

Answer:

Option 2 50 ≤ s ≤ 100

Option 5 She could deposit $50

Option 6 She could deposit $75

Step-by-step explanation:

Let

s -----> amount of money Layla deposit into a saving account

we know that

25%=25/100=0.25

50%=50/100=0.50

$s\geq 0.25*200$ -----> $s\geq \$50$

$s\leq 0.50*200$ -----> $s\leq \$100$

The compound inequality is

$\$50 \leq s\leq \$100$

Verify each case

case 1) 25 ≤ s ≤ 50

The statement is false

see the procedure

case 2) 50 ≤ s ≤ 100

The statement is True

see the procedure

case 3) s ≤ 25 or s ≥ 50

The statement is false

Because is s ≤ 100 and s ≥ 50

case 4) s ≤ 50 or s ≥ 100

The statement is false

Because is s ≤ 100 and s ≥ 50

case 5) She could deposit $50

The statement is true

Because the value of s satisfy the compound inequality $\$50 \leq s\leq \$100$

case 6) She could deposit $75

The statement is true

Because the value of s satisfy the compound inequality $\$50 \leq s\leq \$100$

3 0

4 years ago

Read 2 more answers

2(9+10r)-14 please help

Fittoniya [83]

Answer:

$20r+4$

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B%282x%2B1%29%28x-5%29%7D%7B%28x-5%29%28x%2B4%29%5E%7B2%7D%20%7D" id

dybincka [34]

i) The given function is

$f(x)=\frac{(2x+1)(x-5)}{(x-5)(x+4)^2}$

The domain is

$(x-5)(x+4)^2\ne 0$

$(x-5)\ne0,(x+4)^2\ne 0$

$x\ne5,x\ne -4$

ii) For vertical asymptotes, we simplify the function to get;

$f(x)=\frac{(2x+1)}{(x+4)^2}$

The vertical asymptote occurs at

$(x+4)^2=0$

$x=-4$

iii) The roots are the x-intercepts of the reduced fraction.

Equate the numerator of the reduced fraction to zero.

$2x+1=0$

$2x=-1$

$x=-\frac{1}{2}$

iv) To find the y-intercept, we substitute $x=0$ into the reduced fraction.

$f(0)=\frac{(2(0)+1)}{(0+4)^2}$

$f(0)=\frac{(1)}{(4)^2}$

$f(0)=\frac{1}{16}$

v) The horizontal asymptote is given by;

$lim_{x\to \infty}\frac{(2x+1)}{(x+4)^2}=0$

The horizontal asymptote is $y=0$ .

vi) The function has a hole at $x-5=0$ .

Thus at $x=5$ .

This is the factor common to both the numerator and the denominator.

vii) The function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

6 0

3 years ago

16 times 3/3 is greater than or less than or equal to 16

galina1969 [7]

Less because 3×3=6 and 6 and 16 arent equal

8 0

3 years ago

A rectangular solid is 5 inches wide, 8 inches long, and 3 inches tall. what is the volume of this rectangular solid in cubic in

ella [17]

Answer:

120 i think..?

Step-by-step explanation:

8 0

4 years ago