3 years ago

If you exert a force of 10.0 n to lift a box a distance of 0.9 m how much work do you do

1 answer:

5 0

A bit vague since it's not clear whether the applied force is in the same direction as the box's displacement. But let's assume it is. Then the work done is:

W = Fd

W = work, F = force, d = displacement

Given values:

F = 10.0N, d = 0.9m

Plug in and solve for W:

W = 10.0(0.9)

W = 9J

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If the distance from a light source triples, how does light intensity change? The intensity will be 3x greater. The intensity wi

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Answer:

The intensity will be 1/9 as much.

Explanation:

The intensity of the light or any source is inversely related to the square of the distance.

$I\alpha \frac{1}{r^{2} }$

Now according to the question the distance is increased by three times than,

$\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{r_{2}^{2} }$

Therefore,

$\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{(3r_{1})^{2} }\\\frac{I_{2} }{I_{1} }=\frac{1}{9} \\{I_{2}=\frac{1}{9}{I_{1} }$

Therefore the intensity will become 1/9 times to the initial intensity.

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3 years ago

If Pressure = 1000 Pa and Area = 0.2 m square, then Force

Maksim231197 [3]

Here

Pressure=1000Pa

Area=0.2m Square

Force=?

Now,,

Pressure =force / Area

1000=force/0.2

force=1000/0.2

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2 years ago

A Boy can raise a load of 200N up to a<br>height of 2.5m in 15 seconds. calculate his<br>power

shtirl [24]

Explanation:

f=mg

=200×10

=200N

Now,

work done=df

25×200

=500J

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3 years ago