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4 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics

1 answer:

inysia [295]4 years ago

5 0

Newton' 1st Law of Motion

A soccer ball will not move until a player kicks it

A bowling ball hits the pins sending the pins flying for a STRIKE!

Newton's 2nd Law of Motion

it takes less force to move a ping pong ball then a bowling ball.

f - ma

Newton's 3rd Law of Motion

a fireman turns on his house and is knocked backward

If air is let out of a balloon quickly, air pushes down & balloon goes up

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Which has more PE, the same bowling ball held 5 meters in the air or the ping pong ball held at 5 meters? Explain.

anastassius [24]

Answer:

The bowling ball

Explanation:

The PE (gravitational potential energy) of an object is given by:

$PE=mgh$

where

m is the mass of the object

g is the gravitational acceleration

h is the height of the object above the ground

In this case, we are comparing the PE of a bowling ball and of a ping pong ball. The two balls are located at same height (h=5 m) and the gravitational acceleration is the same (g=9.8 m/s^2), so their PE depends only on their mass: since the bowling ball has a greater mass than the ping pong ball, the bowling ball will have a greater PE.

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4 years ago

Which physical property explains the difference in ability of copper and rubber to transmit electricity?

ludmilkaskok [199]

The copper is a conductor and the rubber is an insulator. Conductors allow electricity to be transmitted freely while insulators prevent most of the current from transmitting. The outer electrons of the conductor's atoms are not very stable and are able to freely move around the material. In a material such as copper, the valence electrons are essentially free and strongly repel each other. The atoms of insulators such as rubber, hold tight to their outer electrons which prevents electricity from flowing freely through.

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4 years ago

Which organism is the primary consumer in this food chain?

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3 years ago

A block of mass 0.490 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x. T

Dennis_Churaev [7]

Answer:

The value of x is $x = 0.1955\ m$

The value of the velocity at the top is $v_{top} = 2.25 \ m/s$

Explanation:

The diagram of this process is on the first uploaded image

From the question we are told that

The mass of the block is $m_b = 0.490kg$

The distance of compression is $x$

The force constant is $k = 450 N/m$

The radius of the circular track is $R =1.00m$

The speed at the bottom of the track is $v_A = 13.4 \ m/s$

The frictional force experienced is $F_f = 7.00 \ N$

Now looking at this process we see that the potential energy of the spring is been transformed into the kinetic energy of the block . So,

$PE \ of \ spring = KE \ of \ block$

mathematically i.e

$\frac{1}{2}k x^2 = \frac{1}{2} m_bv^2_A$

$0.5 * 450 * x^2 = 0.5 * 0.490 * 13.4^2$

Making x the subject of the formula

$x = \sqrt{\frac{0.5 * 0.490 * 13.4^2}{ 0.5 * 450} }$

$= 0.1955\ m$

The average workdone by friction is $W_f = F_f * \pi$

Here $\pi is \ the\ net\ displacement$

$W_f = 7 * 3.142$

$= 21.99 J$

The kinetic energy at the bottom is

$KE = \frac{1}{2} * 0.490 * 13.4^2$

$= 43.99 \ N$

The potential energy gained at the top of the circle is

$PE = m_bgh$

Here h is the height which is equal to d(diameter) = 2r = 2 × 1 = 2 m and

g is acceleration due to gravity $= 9.8m/s^2$

Now substituting values

$PE = 0.490 * 9.8 *2$

$=9.604 J$

Since energy is can not be created nor destroyed but transformed according to first law of thermodynamics

$KE_{at \bottom} = PE _ {\ at \ top } + W_f + KE_{\ at \ top}$

$43.99 = 9.604 +21.99 + [\frac{1}{2} m_b * v_{top} ^2]$

$12.369= [2.45* v_{top} ^2]$

$v_{top} =\sqrt{\frac{12.369}{2.45} }$

$= 2.25 \ m/s$

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Explanation:

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