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mestny [16]
3 years ago
14

why do you think we have different seasons (fall, summer, winter, spring) in certain areas of the world?

Physics
1 answer:
Verizon [17]3 years ago
7 0

Answer:

how the areas are at

Explanation:

The tilt of the Earth's AXIS is the most important reason why seasons occur... The area depends why there's  a certain differnt season on differnt areas , its because one area is closet to the sun which mostky they get summer full time (like a normal year), but  Alaska,it just winter , the reason why Alaska is just cold because its not close to the sun.

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This project will allow you to “see” the difference between AC and DC.
Temka [501]

Answer: uhhhhhhh what is this for?

Explanation i so confused

5 0
3 years ago
Read 2 more answers
Please help on this one!!
inysia [295]

The energy transformations that occur as you coast down long hill on a bicycle, including the brakes to make the bike stop at the bottom, is that at the top of the hill you have high GPE AND LOW KE, on your way down you have HIGH KE AND LOW GPE, and at the bottom you have thermal energy due to the stop of the brakes.

the law of conversation of energy and describe the energy transformations that occur as you coast down a long hill on a bicycle and then apply the brakes to make the bike stop at the bottom.


3 0
3 years ago
A flat circular plate of copper has a radius of 0.262 m and a mass of 61.5 kg.
Evgesh-ka [11]

Answer:

0.031 m

Explanation:

Density of copper = ρ =  8960 kg/m³

r = Radius = 0.262 m

m = Mass of plate = 61.5 kg

v = Volume of plate = Volume of cylinder = πr²h

\rho=\frac{m}{v}\\\Rightarrow 8940=\frac{61.5}{\pi r^2h}\\\Rightarrow h=\frac{61.5}{\pi 0.262^2\times 8940}\\\Rightarrow h=0.031\ m

So, thickness of plate is 0.031 m

5 0
4 years ago
An object is dropped from a very tall bridge. If it takes 29.48 s to reach the ground below, how high is the bridge?////
LenKa [72]

Answer:

ithe bridge is about 3.01 or exactly 3.0081632653

5 0
4 years ago
at what position an object be placed in front of a concave mirror of radius of curvature 40cm so that an erect image of magnific
Thepotemich [5.8K]
  • C=40cm
  • f=C/2=40/2=20

  • m=3

\\ \sf\longmapsto m=\dfrac{f}{f-u}

\\ \sf\longmapsto 3=\dfrac{20}{20-u}

\\ \sf\longmapsto 3(20-u)=20

\\ \sf\longmapsto 60-3u=20

\\ \sf\longmapsto 3u=40

\\ \sf\longmapsto u=13.3cm

  • m=magnification
  • f is focal length
  • C is radius of curvature
  • u is object distance
8 0
3 years ago
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