Answer: 32 room
Step-by-step explanation:
<u>If 1 room = 7.75 yd of carpet ⇒ x rooms = 250 yd of carpet</u>
Use proportions & cross-multiply to solve:
So 250 yd of carpet can cover about 32 rooms.
Problem Solving Method
1 answer:
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Answer:
Step-by-step explanation:
For this case we assume that the total perimeter is 18 ft, we have a wall and the two sides perpendicular to the wall measure x units each one so then the side above measure P-2x= 18-2x.
And we are interested about the maximum area.
For this case since we have a recatangular area we know that the area is given by:
Where L is the length and W the width, if we replace from the values on the figure we got:
And as we can see we have a quadratic function for the area, in order to maximize this function we can use derivates.
If we find the first derivate respect to x we got:
We set this equal to 0 in order to find the critical points and for this case we got:
And if we solve for x we got:
We can calculate the second derivate for A(x) and we got:
And since the second derivate is negative then the value for x would represent a maximum.
Then since we have the value for x we can solve for the other side like this:
And then since we have the two values we can find the maximum area like this:
Answer:
The mean no. of red cubes is more than the median no. of red cubes.
Step-by-step explanation:
According to the question, we can prepare the following table denoting the no. of bags containing any number of red cube(s). The no. of red cubes in each bag can theoretically be any no. between 0 and 20 (both end inclusive) as in total each bag contains 20 cubes of different colors.There are as a whole 10 bags (given).
No. of red cubes No. of bags
0 2 0
1 0 0
2 2 4
3 1 3
4 1 4
5 0 0
6 1 6
7 2 14
8 1 8
9 0 0
10 0 0
Total 10 39
Now, no. of bags containing no. of red cubes above 10 is 0 [since there are as a whole 10 bags only]
So, from the table we get that mean no, of red cubes in each bag
=
= 39/10 = 3.9
Also, from the table, we get that, no. of bags with no. of red cubes ≤ 3
= (2 + 2 + 1) = 5
and, no. of bags with no. of red cubes ≥ 4
= (1 + 1 + 2 + 1) = 5
Also there are 1 bag each for no. of red cubes = 3 and 4
So. median no. of red cubes = (3 + 4)/2 = 3.5
So, we get that the mean no. of red cubes is more than the median no. of red cubes.