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Tasya [4]
3 years ago
11

Find the length of the given segments and determine if they are congruent Simplify DE and RS

Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0

Answer:

The answer is below

Step-by-step explanation:

The complete question is contained in the image.

The distance between points A(x_1,y_1) and B(x_2,y_2) in the coordinate plane is given as:

|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Point D is at (7, 0) and E at (0, -2) hence the distance between the two points is:

|DE|=\sqrt{(0-7)^2+(-2-0)^2}=\sqrt{49+4}=\sqrt{53}=7.28

Point R is at (-7, -7) and S at (3, -3) hence the distance between the two points is:

|RS|=\sqrt{(3-(-7))^2+(-3-(-7))^2}=\sqrt{100+16}=\sqrt{116}=10.77

Since |RS| ≠ |DE|, therefore they are not congruent

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The image shows three tennis balls enclosed in a cylindrical can. Choose all that are correct. The volume of a single tennis bal
Fynjy0 [20]

Answer:

The volume of a single tennis ball is 14.14\ in^{3}

The volume of three tennis balls is 42.42\ in^{3}

Step-by-step explanation:

Step 1

Find the volume of a single tennis ball

we know that

The volume of a sphere is equal to

V=\frac{4}{3}\pi r^{3}

where r is the radius of the sphere

In this problem

r=3/2=1.5\ in

substitute

V=\frac{4}{3}\pi (1.5)^{3}

V=14.14\ in^{3}

Step 2

Find the volume of the can

we know that

the volume of the cylinder is equal to

V=\pi r^{2} h

where r is the radius of the cylinder

h is the height of the cylinder

in this problem we have

r=3/2=1.5\ in

h=8.4\ in

substitute

V=\pi (1.5)^{2}(8.4)

V=59.38\ in^{3}

Statement

<u>case A)</u> The volume of a single tennis ball is 14.14\ in^{3}

The statement is true

See the procedure in Step 1

<u>case B)</u> The volume of the can is 56.55\ in^{3}

The statement is false

The volume of the can is 59.38\ in^{3} --> see the procedure Step 2

<u>case C)</u> The empty space inside the can is 14.13\ in^{3}

The statement is false

To find the empty space subtract the volume of three tennis ball from the volume of the can

59.38\ in^{3}-3*14.14\ in^{3}=16.96\ in^{3}

<u>case D)</u> The volume of three tennis balls is 42.42\ in^{3}

The statement is true

To find the volume of three tennis balls multiply the volume of a single tennis ball by three

14.14*3=42.42\ in^{3}

8 0
3 years ago
How many unique ways are there to arrange the letters in the word DEN?
Tatiana [17]
2 is the correct answer I'm almost definite
5 0
3 years ago
Read 2 more answers
1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch
kykrilka [37]
Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle. 

Thus, half the angle formed by the chord at the centre of the circle is given by:

\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2}  \\  \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o

Now, 

\sin60^o= \frac{9}{r}  \\  \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392

Therefore, the radius of the circle is 10.4 cm to 1 d.p.


Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o

Now, 

\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm


Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

\sin40^o= \frac{y}{10}  \\  \\  \\ \Rightarrow y=10\sin40^o=6.428

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
3 0
3 years ago
What is the equation for the line in slope-intercept form?
asambeis [7]
Y=4x i believe is the answer
3 0
3 years ago
Read 2 more answers
Circle O is inscribed in the given triangle. What is the perimeter of the triangle?
Yuri [45]

Answer:

44 units

Step-by-step explanation:

just answered on edg 2020

4 0
3 years ago
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