Model 1.42 = 100% _% = _%

1 answer:

3 0

For the answer to the equation above, are you asking if what is the 1.42% of 100?
Because the 1.42 of 100% is 1.42

100/x=100/1.42
(100/x)*x=(100/1.42)*x multiply both sides of the equation by x
100=70.422535211268*x divide both sides of the equation by (
70.422535211268) to get x
100/70.422535211268=x 
1.42=x 
x=1.42
I hope my answer helped you. Feel free to ask more questions. If you want some more precise answers to your question, ask the right question to get the right answers. Have a nice day!

You might be interested in

In what time the compound amount of Rs 60000 at 10% rate is rs 79860?

Ksenya-84 [330]

Answer:

P= Rs 60000

A= Rs 79860

T=1 & 1/2 year = 3/2 years

= 3/2 x 2 = 3 half years

R= ?

Applying the formula A= P (1+r/100)^T

79860 = 60000 (1+ r/100)^3

79860/60000 = (1+r/100)^3

1331/1000 = (1+r/100)^3

root(3)(1331/1000) = (1+r/100)

11/10 = 1+r/100

11/10 -1 = r/100

1/10 = r/100

r= 10 %

Step-by-step explanation:

8 0

3 years ago

26.891 to the nearest ten thousands place

Ahat [919]

the number isn't large enough to round to the nearest ten thousandths.

that would be the 4th digit to the right of the decimal point, so we would need the 4th and 5th numbers to the right in order to round the answer.

6 0

3 years ago

The length of time a person takes to decide which shoes to purchase is normally distributed with a mean of 8.21 minutes and a st

madam [21]

Answer:

4.55% probability that a randomly selected individual will take less than 5 minutes to select a shoe purchase.

Since Z > -2 and Z < 2, this outcome is not considered unusual.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If $Z \leq 2$ or $Z \geq 2$ , the outcome X is considered to be unusual.