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bulgar [2K]
2 years ago
14

Help please!!!!

Mathematics
1 answer:
wolverine [178]2 years ago
3 0

Answer:

2nd statement is false

Step-by-step explanation:

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Describe the error(s) that occurred and show the correct solution.
RideAnS [48]

Answer:

-x^{2}+4x

Step-by-step explanation:

we have

(x^{2}+x)-(2x^{2} -3x)

step 1

Eliminate the parenthesis

x^{2}+x-2x^{2} +3x

The symbol of the term 3x is incorrect, must be positive instead of negative

so

-(-3x)=+3x

Group terms that contain the same variable

(x^{2}-2x^{2})+(x+3x)

Combine like terms

-x^{2}+4x

6 0
3 years ago
Simplify expression<br>8x-6+x-1​
charle [14.2K]

Answer:

9x -7

Step-by-step explanation:

8x-6+x-1​

Combine like terms

8x +x   -6-1

9x -7

8 0
3 years ago
Find the remainder when x⁴+x³-2x²+x+1 divided by x+1​
Zolol [24]

Answer:

\frac{-2}{x+1}

Step-by-step explanation:

x^3-2x+3-\frac{2}{x+1}

also if ur brainly staff and seeing this

plz remove/delete my account asap tysm

5 0
3 years ago
What is the solution to the inequality?<br> −6x+5&gt;−1
Bogdan [553]

Answer:

\boxed{x

Step-by-step explanation:

-6x+5>-1\qquad\text{subtract 5 from both sides}\\\\-6x>-6\qquad\text{change the signs}\\\\6x

3 0
3 years ago
MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
1 year ago
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