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2 years ago

Help please!!!!

Mathematics

1 answer:

wolverine [178]2 years ago

3 0

Answer:

2nd statement is false

Step-by-step explanation:

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Describe the error(s) that occurred and show the correct solution.

RideAnS [48]

Answer:

$-x^{2}+4x$

Step-by-step explanation:

we have

$(x^{2}+x)-(2x^{2} -3x)$

step 1

Eliminate the parenthesis

$x^{2}+x-2x^{2} +3x$

The symbol of the term 3x is incorrect, must be positive instead of negative

$-(-3x)=+3x$

Group terms that contain the same variable

$(x^{2}-2x^{2})+(x+3x)$

Combine like terms

$-x^{2}+4x$

6 0

3 years ago

Simplify expression 8x-6+x-1

charle [14.2K]

Answer:

9x -7

Step-by-step explanation:

8x-6+x-1

Combine like terms

8x +x -6-1

9x -7

8 0

3 years ago

Find the remainder when x⁴+x³-2x²+x+1 divided by x+1

Zolol [24]

Answer:

$\frac{-2}{x+1}$

Step-by-step explanation:

$x^3-2x+3-\frac{2}{x+1}$

also if ur brainly staff and seeing this

plz remove/delete my account asap tysm

5 0

3 years ago

What is the solution to the inequality? −6x+5>−1

Bogdan [553]

Answer:

$\boxed{x$

Step-by-step explanation:

$-6x+5>-1\qquad\text{subtract 5 from both sides}\\\\-6x>-6\qquad\text{change the signs}\\\\6x$

3 0

3 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

1 year ago