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4 years ago

2.13786*10^4 written in standard form

Mathematics

1 answer:

never [62]4 years ago

7 0

Rewritten is 2.3786x10000.

So, this is going to be 2x10000+0.3x10000+0.07x10000+0.008x10000+0.0006x10000. Therefore, written in standard form looks like: 2x10000+0.3x10000+0.07x10000+0.008x10000+0.0006x10000

Hope this answered your question.

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oksano4ka [1.4K]

Answer:

x=9

Step-by-step explanation:

dyyfjfjsjujsjsivjsjicuejie82iu3828i$>÷>$>$>×&$:

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Factor p^2-q^2-2p+2q

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Not sure of the answer but i know what factors
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In a lab, a scientist is growing bacteria for a study. The scientist begins with a bacteria

Diano4ka-milaya [45]

Answer:

The answer is below

Step-by-step explanation:

The growth of the bacteria is in the form of an exponential growth. It is given by the formula:

$P(t)=ae^{rt}\\\\where\ t\ is\ the\ number\ of \ hours, P(t)\ is\ the \ population\ at\ t\ hours\\\and\ a=population\ at\ start$

At 2 hours, the population is 62 cells, hence:

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After another 2 hours (4 hours), the population is 1 million:

$P(4)=ae^{4r}\\\\1000000=ae^{4r}\ \ .\ \ .\ \ .\ (2)\\\\Divide \ equation\ 2\ by\ equation\ 1:\\\\\frac{1000000}{62}=\frac{ae^{4r}}{ae^{2r}} \\\\16129=e^{2r}\\\\ln(e^{2r})=ln(16129)\\\\2r=9.688\\\\r=4.844$

Put r = 4.844 in equation 1

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4 years ago

The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.05

Tresset [83]

Answer:

(a) Probability that there are no surface flaws in an auto's interior is 0.6065 .

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws is 0.00673 .

Step-by-step explanation:

We are given that the number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.05 flaws per square foot of plastic panel.

Let X = Distribution of number of surface flaws in plastic panels

So, X ~ Poisson( $\lambda$ )

The mean of Poisson distribution is given by, E(X) = $\lambda$ = 0.05

which means, X ~ Poisson(0.05)

The probability distribution function of a Poisson random variable is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!}; for x=0,1,2,3...$

Now, we know that $\lambda$ for per square foot of plastic panel is 0.05 and we are given that an automobile interior contains 10 square feet of plastic panel.

Therefore, for 10 square foot of plastic panel is = 10 * 0.05 = 0.5

(a) Probability that there are no surface flaws in an auto's interior =P(X=0)

P(X = 0) = $\frac{e^{-0.5}*0.5^{0}}{0!}$ = $e^{-0.5}$ = 0.6065

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws = $P(X = 0)^{10}$

So, $P(X = 0)^{10}$ = $0.6065^{10}$ = 0.00673

8 0

3 years ago