Answer: The correct option would be A.
Explanation: The main group elements which make more bonds than that was predicted from the octet rule are supposed to have expanded octet.
These elements tend to have more than 8 valence electrons after bonding and this can be achieved when we have empty d-orbitals.
When we have empty p-orbitals, total number of valence electrons than can be occupied will be 8.
Electronic configuration when valence shell's empty p-orbitals are fully filled = 
which means that a total of 8 electrons can be occupied which does not satisfy expanded octet rule.
Example of molecule showing expanded octet rule is given in the image. Here, after bonding Phosphorous has 10 electrons which is occupied in empty d-orbitals.
Answer: If this atom loses one electron, it will become a cation with a 1+ charge
Explanation:
there is not enough information to make a prediction as we dont know what side she taped on magnet C
Ionic molecules have higher boiling point than covalent molecules.
So that leaves Na2SO4 and NaCl.
The ionic molecule with higher charge will have higher boiling point.
Na2SO4 have ions with charge +-2.
NaCl have ions with charge +-1.
So the answer is C.