Question

onsider the reaction, which takes place at a certain elevated temperature CO(g)+NH3(g)⇌HCONH2(g), Kc=0.860 If a reaction vessel initially contains only CO and NH3 at concentrations of 1.00 M and 2.00 M, respectively, what will the concentration of HCONH2 be at equilibrium?

Answer 1

Answer:

concentration of HCONH2 at equillibrium is 0.5 M

Explanation:

                               CO(g) + NH3(g) ⇌ HCONH2(g)

-vessel iniatial             1             2                 0

concentration

-equillibrium              1-x         2-x               x

concentration

                                $K_{C} = (CO)\times (NH_{3})/ (HCONH_{2})$

                               0.860 = (1-x)(2-x) / x

                                 $x^{2}-3.86x+2$

                                  $x = 3 , 0.5$

         concentration of HCONH2 at equillibrium is 0.5 M