gravity dwn, your hand up and equal to grav
Answer:
The speed of the combined vehicles is 6.82m/s
Explanation:
Using the law of conservation of momentum which stayed that the sum of momentum of bodies before collision is equal to their sum of momentum after collision. After collision, both object moves with the same velocity.
Momentum = mass×velocity
Before collision:
Momentum of vehicle or mass 3000kg moving with velocity 25m/s
= 3000×25
= 75000kgm/s
Pa = 75000kgm/s
Momentum of vehicle with mass 2500kg moving with velocity of -15m/s
= 2500×-15
= -37500kgm/s
After collision:
Momentum = (3000+2500)V
Where v is their common velocity
Momentum after collision = 5500V
Based on the law:
75000+(-37500) = 5500V
75000-37500 = 5500V
37500 = 5500V
V = 37500/5500
V = 6.82m/s
Answer:
95.78125%
18000 m/s
22233.33 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
The velocity of the rocket at the end of the first 15 minutes is 18000 m/s which is the maximum speed of the rocket in the complete journey.
Distance traveled while speeding up
Distance traveled while slowing down
Distance traveled during constant speed
Fraction
Fraction of the total distance is traveled at constant speed is 95.78125%
Time taken at constant speed
Total time taken is 
Answer:
3,13 N
Explanation:
Del enunciado de la segunda ley del movimiento de Newton;
F = ma
Dónde;
F = Fuerza aplicada
m = masa del cuerpo
a = aceleración del cuerpo
Sustitución de valores;
F = 5,9 kg * 0,53 m / seg2 = 3,13 N
Por tanto, la fuerza aplicada es 3,13 N
