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Brut [27]
3 years ago
6

A rectangular photo has a frame that is 1 inch wide. If the photo is twice as long as it is wide and the area of the photo and f

rame together is 60 inches, what are the dimensions of the photo?
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer: the length is 8 inches

The with is 4 inches

Step-by-step explanation:

Let L represent the length of the photo.

Let W represent the width of the photo.

If the photo is twice as long as it is wide, it means that

L = 2W

The rectangular photo has a frame that is 1 inch wide. This means that

The length of the photo and the frame is L + 2

The width of the photo and the frame is W + 2

If the area of the photo and frame together is 60 inches², it means that

(L + 2)(W + 2) = 60 - - - - - - - - - - -1

Substituting L = 2W into equation 1, it becomes

(2W + 2)(W + 2) = 60

2W² + 4W + 2W + 4 = 60

2W² + 6W + 4 - 60 = 0

2W² + 6W - 56 = 0

Dividing through by 2, it becomes

W² + 3W - 28 = 0

W² + 7W - 4W - 28 = 0

W(W + 7) - 4(W + 7) = 0

(W - 4)(W + 7) = 0

W = 4 or W = - 7

The width cannot be negative , therefore, W = 4

Substituting W = 4 into L = 2W, ut becomes

L = 2 × 4 = 8 inches

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