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Diano4ka-milaya [45]
3 years ago
14

Jerry has taken a random sample of students and determined the number of electives that each student in his sample took last yea

r. There were 19 students in the sample. Here is the data on the number of electives the 19 students took: 6, 6, 8, 7, 7, 7, 8, 9, 10, 8, 7, 6, 9, 6, 8, 7, 9, 7, 10. The mean of this sample data is 7.63. What is the sample proportion of students who took fewer than the mean number
of electives?

A: 10/19
B: 6/19
C: 7/19
D: There is not enough data to answer this question.
Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0
<span>The sample proportion of the the students that took fewer than the mean number of electives is given by the number of people who took less that the mean number of electives (i.e. 7.63) divided by the total number of students in the sample (i.e. 19). The total number of people who took less than 7.63 electives is 10. Therefore, the required sample proportion is 10 / 19. </span>
Nata [24]3 years ago
5 0

Answer:10/19

Step-by-step explanation:

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Step-by-step explanation:

The NTH term of an Arithmetic Sequence is given as

an = a1 + (n - 1 ) d

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the first term

an = a1 + (n - 1 ) d = 8+(1-1) 2

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second term=

an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2

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3rd term

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6th term

an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2

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