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3 years ago

AAAHH I NEED A ANSWER ASAP IM BEING TIMED

Mathematics

1 answer:

Zanzabum3 years ago

5 0

I cant see the whole question please provide more details

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What is the theoretical probability, as a percent, of flipping heads?

Rufina [12.5K]

I would say 50/50 chance because it can go ether ways one can go heads the others can go tails

5 0

3 years ago

Look at the diagram. If RS= 8y + 4, ST = 4y + 8, and RT = 36, find the value of y.

vladimir2022 [97]

RS= 8y + 4, ST = 4y + 8, and RT = 36

RS + ST = RT
8y + 4 + 4y + 8 = 36
12y + 12 = 36
12y = 24
y = 2

answer
y = 2 (first choice)

6 0

3 years ago

Read 2 more answers

Please help with that answer someone please before 12:00an

nata0808 [166]

Answer:

150 cause subtract 150 from 270 you get 150

8 0

3 years ago

Read 2 more answers

How would I do the steps to solve this?

allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

$R(p) = -10p^2+800p$

Taking derivative wrt p

$\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\$

Now putting R'(p) = 0

$-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40$

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

$R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000$

The maximum revenue is 16000 dollars (at p = 40)

3 0

2 years ago

Consider the following functions.G(x) = 4x2; f(x) = 8x(a)

noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form $4x^2+C$ is an antiderivative of 8x

Step-by-step explanation:

A function F is an antiderivative of the function f if

$F'(x)=f(x)$

for all x in the domain of f.

(a) If $f(x) = 8x$ , then $G(x)=4x^2$ is an antiderivative of f because

$G'(x)=8x=f(x)$

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of f.

(b) Because

$\frac{d}{dx}(4x^2)=8x$

then $G(x)=4x^2$ is an antiderivative of $f(x) = 8x$ . Therefore, every antiderivative of 8x is of the form $4x^2+C$ for some constant C, and every function of the form $4x^2+C$ is an antiderivative of 8x.

8 0

3 years ago