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vlada-n [284]
3 years ago
6

Make a congestion if you know that a relationship is proportional and are given one ordered pair that is not (0,0) how can you f

ind another pair
Mathematics
1 answer:
IRISSAK [1]3 years ago
7 0
When you know that a relationship is proportional and you know one ordered pair that is not (0,0) you can find another (any) pair x,y by doing y / x = constant.

So, with the given pair you find the ratio y / x. Suppose this ratio is:

y / x = k

Now you multiply any x-value times k to find the correspondant y-value.
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There are twenty cards labeled from 1 to 20 in a bag. A card is randomly selected from the bag.
AveGali [126]
If you are asking for the probability of getting a certain card you have a 1/ 20th  chance

If you are asking for a percentage there is a 5% chance of getting any card
4 0
3 years ago
Ben uses a compass and straightedge to bisect segment PQ, as shown: segment PQ with compass open to greater than half of segment
il63 [147K]

Answer: To be able to create two intersecting arcs above and below the line segment

Step-by-step explanation:

That is one of the steps to bisecting a line segment lol

7 0
3 years ago
In a research lab, a cell biologist is growing a strain of bacteria under two different conditions. Culture A had an initial pop
zhannawk [14.2K]

Answer:

They will have the same population after 6 hours

Step-by-step explanation:

The general exponential equation format for this is;

P = P_o(e^(kt))

For Culture A, we are told that it had an initial population of 200 and doubles every hour.

Thus;

After 1 hour, P = 400

After 2 hours, P = 800

After 3 hours, P = 1600

Thus;

At t = 1, we have;

400 = 200(e^(k × 1))

400/200 = e^(k)

e^(k) = 2 - - - (eq 1)

At t = 2, we have;

800 = 200(e^(k × 2))

800/200 = e^(2k)

e^(2k) = 4 - - - (eq 2)

To find k, let's divide eq 1 by eq 2.

(e^(2k))/e^(k) = 4/2

e^(2k - k) = 2

e^(k) = 2

k = In 2

k = 0.6931

Thus;

P = 200e^(0.6931t)

For Culture B, we are told that it had an initial population of 819200 but has been contaminated. Its population is now decreasing by half every hour.

Thus;

After 1 hour, P = 409600

After 2 hours, P = 204800

After 3 hours, P = 102400

Thus;

At t = 1, we have;

409600 = 819200(e^(k × 1))

409600/819200 = e^(k)

e^(k) = 0.5 - - - (eq 1)

At t = 2, we have;

204800 = 819200(e^(k × 2))

204800/819200 = e^(2k)

e^(2k) = 0.25 - - - (eq 2)

To find k, let's divide eq 1 by eq 2.

(e^(2k))/e^(k) = 0.25/0.5

e^(k) = 0.5

k = In 0.5

k = -0.6931

Thus;

P = 819200(e^(-0.6931t))

We want to find the time when the 2 cultures will have the same population. Thus;

200e^(0.6931t) = 819200(e^(-0.6931t))

Arranging, we have;

(e^(0.6931t))/(e^(-0.6931t)) = 819200/200

e^(0.6931t - (-0.6931t) = 4096

e^(1.3862t) = 4096

1.3862t = In 4096

1.3862t = 8.3178

t = 8.3178/1.3862

t ≈ 6 hours

3 0
4 years ago
What is the y value​
slega [8]

Answer:

The y value is on agraph the up and down line

Step-by-step explanation:

5 0
4 years ago
7. The difference of Grandma Annie's age and twice Carl's is 22. Gran
OlgaM077 [116]
<h2>Systems of Equations Word Problems</h2>

To solve these questions, we can translate key words into operations:

  • <em>Difference</em> = subtract
  • <em>Twice</em> = double
  • <em>Less than</em> = subtract

<h2>Solving the Question</h2>

We're given:

  • Difference of Annie's age and twice Carl's age is 22
  • Annie's age is 13 less than 3 times Carl's age

There are two variables given two us: Annie's age and Carl's age.

  • Let Annie's age be equal to <em>x.</em>
  • Let Carl's age be equal to <em>y</em>.

Translate the given information into two equations:

  • Difference of Annie's age and twice Carl's age is 22
    ⇒ x-2y=22
  • Annie's age is 13 less than 3 times Carl's age
    ⇒ x=3y-13

Now, we can substitute the fist equation into the second one to solve for <em>y</em>:

(3y-13)-2y=22\\3y-13-2y=22\\y-13=22\\y=35

Now, substitute <em>y</em> back into the second equation to solve for <em>x</em>:

x=3y-13\\x=3(35)-13\\x=105-13\\x=92

<h2>Answer</h2>

Therefore, Grandma Annie is 92 years old.

6 0
3 years ago
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