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Crazy boy [7]
4 years ago
8

Write an inequality to match each description. Use n for the variable.

Mathematics
1 answer:
mel-nik [20]4 years ago
6 0

{\huge {\mathfrak {Answer :-}}}

Let, the length be l and breadth be b.

So, 2(l + b) = 26

Or, l + b = 13

Or, l = 13 - b

So, we may write like this,

Area = l * b

Or, l * b > 30

Or, l (13 - l) > 30

Or, 13l - l^2 > 30

Or, l^2 - 13l + 30 > 0

Or, l^2 - 3l - 10l + 30 > 0

Or, l(l - 3) - 10(l - 3) > 0

Or, (l - 3)(l - 7) > 0

Or, l - 7 > 0

Or, l > 7.

Now, putting the value of l,

We get, l * b > 30

Or, 7 * b > 30

Or, b > 30/7

➡️ Therefore, we get,

Length > 7

Breadth > 30/7

That's it..

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alexgriva [62]
Hey there (again)

x = 2y  \\ y = -2  \\ x = 2(-2) \\x= -4 \\ \\ \\ w + xy + 4x^2  = 2\\ w+-4(-2) + 3(-4)^2 = 2 \\ w + 8 + 3(16) = 2 \\ w + 8 + 48 = 2 \\ Subtract56: w + 56 =2 \\ 56 - 56 (Cancel) \\ 2 - 56 = -54 \\ w = -54

Answer: B  the simplification performed in step 2 is invalid or incorrect

Good luck on your assignment and enjoy your day 

~MeIsKaitlyn:)
5 0
3 years ago
6-10 divide, another onee thank you!!​
eduard

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

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Step-by-step explanation:

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