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We have a probability of for the first card to be a diamond. Having drawn this first card <em>without replacement,</em> there are now 12 diamonds remaining in a deck of 51 cards, so the probability that the second card is a diamond, given that the first card was a diamond, is
Similarly, for the third card, there are 11 diamonds in a deck of 50, so the probability of drawing a third diamond is
Now, since these events are dependent, we multiply these three probabilities to get our answer of