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Travka [436]
3 years ago
7

If a gas in a closed container is pressurized from 14.9 atm to 16.5 atm and its original temperature was 33.1 °C, what would the

final temperature of the gas be?
Chemistry
1 answer:
balandron [24]3 years ago
6 0

Answer: 339K

Explanation:

Initial pressure P1 = 14.9 atm

Final pressure P2 = 16.5 atm

Original temperature T1 = 33.1 °C

Convert Celsius to Kelvin

(33.1°C + 273 = 306.1K)

Final temperature T2 = ?

Apply the formula for Pressure's law

P1/T1.= P2/T2

14.9atm/306.1K = 16.5atm/ T2

To get T2, cross multiply

14.9 x T2 = 16.5 x 306.1

14.9T2 = 5050.65

T2 = (5050.65/14.9)

T2 = 339K

Thus, the final temperature of the gas would be 339K

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The movement of substances may occur across a semi‐permeable membrane (such as the plasma membrane). A semi‐permeable membrane allows some substances to pass through, but not others.

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How can you measure the volume of air inside of a balloon?
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You could let the air out of the balloon while it is under the water with a container filled with water upside down over it. And measure the water displacement.

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2 years ago
The change of matter, solid, liquid and gas is called a_________.
valkas [14]

Answer:

This would be a phase change

Explanation:

Since the diffrent phases solid,liquid,gas are changing to other phases.

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Question 24 (1 point)
aleksley [76]

Answer:

Explanation:

Idk

4 0
3 years ago
Given the following: [G3P] = 1.5x10-5M; [BPG] = 3.0x10-3M ; [NAD+] = 1.2x10-5M; [NADH]=1.0x10-4 ; [HPO42-]= 1.2x10-5 M; pH = 7.5
mel-nik [20]

<u>Answer:</u> The given reaction is non-spontaneous in nature.

<u>Explanation:</u>

To calculate the H^+ concentration, we use the equation:

pH=-\log[H^+]

We are given:

pH of the solution = 7.5

7.5=-\log [H^+]

[H^+]=10^{-7.5)=3.1\times 10^{-8}M

For the given chemical equation:

\text{Glyceraldehyde3-phosphate }+NAD^++HPO_4^{2-}\rightarrow \text{1,3-Biphosphoglycerate }+NADH+H^+

The equation used to Gibbs free energy of the reaction follows:

\Delta G=\Delta G^o+RT\ln K_{eq}

where,

\Delta G = free energy of the reaction

\Delta G^o = standard Gibbs free energy = 6.3 kJ/mol = 6300 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[273+25]K=298K  

K_{eq} = Ratio of concentration of products and reactants = \frac{[BPG][NaDH][H^+]}{[G_3P][NAD^+][HPO_4^{2-}]}

[BPG]=3.0\times 10^{-3}M

[NADH]=1.0\times 10^{-4}M

[H^+]=3.1\times 10^{-8}M

[G_3P]=1.5\times 10^{-5}M

[NAD^+]=1.2\times 10^{-5}M

[HPO_4^{2-}]=1.2\times 10^{-5}M

Putting values in above equation, we get:

\Delta G=6300J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(3.0\times 10^{-3})\times (1.0\times 10^{-4})\times (3.1\times 10^{-8})}{(1.5\times 10^{-5})\times (1.2\times 10^{-5})\times (1.2\times 10^{-5})}))\\\\\Delta G=9917.02J/mol=9.92kJ/mol

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

As, the Gibbs free energy of the reaction is positive. The reaction is said to be non-spontaneous.

Hence, the given reaction is non-spontaneous in nature.

4 0
3 years ago
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