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Travka [436]
3 years ago
7

If a gas in a closed container is pressurized from 14.9 atm to 16.5 atm and its original temperature was 33.1 °C, what would the

final temperature of the gas be?
Chemistry
1 answer:
balandron [24]3 years ago
6 0

Answer: 339K

Explanation:

Initial pressure P1 = 14.9 atm

Final pressure P2 = 16.5 atm

Original temperature T1 = 33.1 °C

Convert Celsius to Kelvin

(33.1°C + 273 = 306.1K)

Final temperature T2 = ?

Apply the formula for Pressure's law

P1/T1.= P2/T2

14.9atm/306.1K = 16.5atm/ T2

To get T2, cross multiply

14.9 x T2 = 16.5 x 306.1

14.9T2 = 5050.65

T2 = (5050.65/14.9)

T2 = 339K

Thus, the final temperature of the gas would be 339K

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Explanation :

Formula used  :

\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]

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V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

The given molecule is, CH_3^+

\text{Number of electron pair}=\frac{1}{2}\times [4+3-1]=3

That means,

Bond pair = 3

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The number of electron pair are 3 that means the hybridization will be sp^2 and the electronic geometry of the molecule will be trigonal planar.

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A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm
Ulleksa [173]

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100

Percent error = \frac{0.1}{63.2}\times 100

Percent error = 0.00158\times 100

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100

Percent error = \frac{0.2}{63.2}\times 100

Percent error = 0.00316\times 100

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100

Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100

Percent error = \frac{(0.5)}{63.2}\times 100

Percent error = 0.00791\times 100

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%




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