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Fudgin [204]
3 years ago
7

Both protons and neutrons (and their anti-particles) froze out:

Chemistry
1 answer:
VladimirAG [237]3 years ago
6 0
I think Both protons and neutrons (and their anti-particles) froze out at 1013 K, about 0.0001 seconds after the Big Bang. Protons and neutrons are sub atomic particles of an atom that are found in the nucleus of an atom. Proton is the positively charge particle while the neutron has no charge. The proton positive charge accounts for the positive nuclear charge. 
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The most important ore of aluminum is _____ show the chemical formula ​.​
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Answer:

The most important ore of aluminum is<u> Bauxite.</u>

And its chemical formula is Al_2O_3.2H_2O.

Explanation:

Bauxite is the most important ore of Aluminium from which Aluminium is extracted. Bauxite is a rock and composed of Aluminium bearing mineral.

And its chemical formula is Al_2O_3.2H_2O.

It contains Gibbsite, Bohmite and Diaspore along with iron.

It is a soft material with somewhat white to grey to reddish brown in colour.

It has an earthy lustre and low specific gravity.

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5 0
3 years ago
Why is pure silicon a poor conductor at room temperature brainly
trapecia [35]
Pure silicon is a poor conductor at room temperature because it has 4 valence electrons
4 0
3 years ago
8. What type of reaction is this:
arsen [322]

Answer:

The reaction mentioned in the question is a decomposition reaction.

Explanation:

Decomposition reaction is a specific type of chemical reaction in which the reactant molecule undergo break down to generate its respective products.

 NaCl ⇒ Na + Cl2

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3 0
3 years ago
Read 2 more answers
Pure carbon dioxide (PCO2 = 1 atm) decomposes at high temperature. For the reaction system 2 〖CO〗_2 (g) ⇌2 CO(g)+ O_2 (g) Is thi
julia-pushkina [17]

Answer:

The reaction decomposes more as T increases, therefore it is ENDOTHERMIC, meaning it requires energy to form CO and O₂.

Kp for each specie...

Kp = CO^2 O2 / (CO2)^2

for

T = 1500

Assume 1 atm for CO2, after % dissociation

P-CO2 left = 1*(1-0.048/100)= 0.99952

P-CO formed = 1-0.99952 = 0.00048

P-O2 = (1-0.99952)/2 = 0.00024

so..

Kp = CO^2 O2 / (CO2)^2

Kp = (0.00048^2)(0.00024) / (0.99952^2) = 5.53*10^-11

T = 2500

Assume 1 atm for CO2, after % dissociation

P-CO2 left = 1*(1-17.6/100)= 0.824

P-CO formed = 1-0.824= 0.176

P-O2 = (1-0.176)/2 = 0.088

so..

Kp = CO^2 O2 / (CO2)^2

Kp = (0.176^2)(0.088) / (0.824^2) =0.0040

T = 3000

Assume 1 atm for CO2, after % dissociation

P-CO2 left = 1*(1-54.8/100)= 0.452

P-CO formed = 1-0.452= 0.548

P-O2 = (1-0.452)/2 = 0.274

so..

Kp = CO^2 O2 / (CO2)^2

Kp = (0.548^2)(0.274) / (0.452^2) =0.4027

Explanation:

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3 years ago
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