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pochemuha
4 years ago
13

Acids increase the concentration of __________ in a solution

Chemistry
2 answers:
Rufina [12.5K]4 years ago
3 0
A. hydroxide is the answer
Kaylis [27]4 years ago
3 0
Acids increase the concentration of A. Hydroxide

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What are some possible consequences if transgenic salmon would escape from their pens into the ocean population?
Elenna [48]

Answer:

In this fragile environment, genetically engineered fish would compete with their wild counterparts for food and space, and could even potentially interbreed with them. They will also bring new diseases and cause changes to basic food webs and ecosystem processes that are difficult to anticipate.

Explanation:

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5 0
2 years ago
What is the balance of NH3+HCL=NH4CL+H2O
Karolina [17]

Answer:

Hydrogen chloride react with ammonium hydroxide

HCl + NH3•H2O → NH4Cl + H2O

Explanation:

3 0
3 years ago
A sample of gas has a pressure of 100.0 KPa and 25C. Calculate the pressure if the temperature is changed to 125C while the volu
atroni [7]

Answer:

133.56kPa

Explanation:

Applying Pressure Law,

P/T = P'/T'....................... Equation 1

Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.

From the question, we were asked to calculate P'

There, we make P' the subject of the equation

P' = PT'/T...................... Equation 2

Given: P = 100kPa, T = 25°C = (273+25) = 298K, T' = 125°C = (273+1250K = 398 K

Substitute these values into equation 2

P' = (100×398)/298

P' = 133.56kPa

Hence the pressure is 133.56kPa

6 0
3 years ago
3) A saturated solution of PbCl2 in water was prepared and filtered. From the filtrate (solution collected after filtration), 50
qaws [65]

Answer: a) 0.0144mol/L

b) 1.19\times 10^{-5}

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}

The equation for the ionization of the PbCl_2 is given as:

We are given:

Solubility of PbCl_2 = \frac{2.0g}{0.5L}=4g/L

Molar Solubility of PbCl_2 = \frac{4g/L}{278.1g/mol}=0.0144mol/L

1 mole of PbCl_2 gives 1 mole of Pb^{2+} and 2 moles of Cl^- ions

Solubility product of PbCl_2 = [Pb^{2+}][Cl^-]^2

K_{sp}=[0.0144][2\times 0.0144]^2

K_{sp}=1.19\times 10^{-5}

Thus the solubility product constant is 1.19\times 10^{-5}

4 0
3 years ago
In 1953, who devopled the model that is shown below
PilotLPTM [1.2K]
What model? can you screenshot it or send a link?
7 0
3 years ago
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