Question 1 (1 point)
1 answer:
You might be interested in
The required probability is
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that,
Probability for first draw to be non-defective
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective
(printers after first slot = 10; total defective printers = 2)
Then, total probability
Answer:
Step-by-step explanation:
El cos(α) se define como el cociente entre el cateto adyacente y la hipotenusa.
El valor del cateto adyacente en nuestgro caso es CA = 3.
La hipotenusa se calcual de la siguiente manera:
Por lo tanto, el cos(α) sera:
El cosec(α)=h/CO.
El cateto opuesto CO = 4 y la hipotenusa h = 5
Por lo tanto, el cosec(α) sera:
Espero te haya sido de ayuda!