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lidiya [134]
3 years ago
14

Two long parallel wires each carry a current of 5.0 A directed to the east. The two wires are separated by 8.0 cm. What is the m

agnitude of the magnetic field at a point that is 5.0 cm from each of the wires
Physics
1 answer:
quester [9]3 years ago
7 0

Answer:

24μT

Explanation:

According to the question the horizontzal component of the field at P are equal and opposite therefore, it will get cancelled.

And vertical components will be added

So, net magnetic field will be B_{net}

B_{net}= 2Bsinθ

B=\frac{\mu _{0}I}{2\pi\times5\times10^{-2}}=\frac{2\times10^{-7}\times5}{5\times10^{-2}}

B=2\times10^{-5}T

therefore, B_{net}=2\times2\times10^{-5}\times [\tex][tex]\frac{3}{5}            ( sinθ=3/5)

on calculating we get B_{net}= 24μT

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A box is 4 m in the air and has 120 J of potential energy. What is the box's mass
hodyreva [135]

Answer:

Mass of the box is 3.06 kg

Explanation:

Potential energy (that depends on gravity) is the type of energy which is stored that relies on the general position of different parts of a body.  It is a property of a framework and not of an individual body or molecule; the framework made out of the Earth and the raised ball.

P.E = m.g.h                       Equation(1)

as we have to find the mass of the box then the formula for the mass will become

m=P.E/g(h)                      Equation(2)

as we know

P.E= 120J

h=4m

g=9.8m/s  

g is the gravitational acceleration

putting values in the equation(2)  

m = 120/9.8(4)

    = 120/39.2                    

    = 3.06 kg

mass of the box is 3.06 kg

 


5 0
4 years ago
Explain how all three of Newton’s Laws of Motion apply to weightlifting.
Lubov Fominskaja [6]

Answer:

Newton's first law, an object will stay at rest only if there are no external forces acting on the object or if the net external force acting on the object is zero. Since the barbell is at rest (not moving), the net external force acting on it must be zero

Newton's Second Law of Motion via the equation f = ma, or put differently, force is equal to mass multiplied by acceleration. To generate more force, we must either increase mass or acceleration (or both)

Newton's Third Law of Motion is known as the equal and opposite reaction principle

7 0
4 years ago
The tonga trench in the pacific ocean is 36,000 feet deep. assuming that sea water has an average density of 1.04 g/cm3, calcula
MakcuM [25]
1110 atm    

Let's start by calculating how many cm deep is 36,000 feet. 

 36000 ft * 12 in/ft * 2.54 cm/in = 1097280 cm   

 Now calculate how much a column of water 1 cm square and that tall would mass. 

 1097280 cm * 1.04 g/cm^3 = 1141171.2 g/cm^2   

 We now have a number using g/cm^2 as it's unit and we desire a unit of Pascals ( kg/(m*s^2) ).  

 It's pretty obvious how to convert from g to kg. But going from cm^2 to m is problematical. Additionally, the s^2 value is also a problem since nothing in the value has seconds as an unit. This indicates that a value has been omitted. We need something with a s^2 term and an additional length term. And what pops into mind is gravitational acceleration which is m/s^2. So let's multiply that in after getting that cm^2 term into m^2 and the g term into kg.   

 1141171.2 g/cm^2 / 1000 g/kg * 100 cm/m * 100 cm/m = 11411712 kg/m^2 

 11411712 kg/m^2 * 9.8 m/s^2 = 111834777.6 kg/(m*s^2) = 111834777.6 Pascals   

 Now to convert to atm 

 111834777.6 Pa / 1.01x10^5 Pa/atm = 1107.2750 atm   

 Now we gotta add in the 1 atm that the atmosphere actually provides (but if you look closely, you'll realize that it won't affect the final result). 

 1107.274 atm + 1 atm = 1108.274 atm   

 And finally, round to 3 significant figures since that's the accuracy of our data, giving 1110 atm.
8 0
3 years ago
One problem with weight training as a way to improve overall health is that the results of a weight-training program are not mea
Ede4ka [16]

One problem with weight training as a way to improve overall health is that the results of a weight-training program are not measurable.

B.False

5 0
3 years ago
Read 2 more answers
This 200-kg horse ran the track at a speed of 5 m/s. What was the average kinetic energy?
MrRissso [65]

Answer:

<h2>2500 J</h2>

Explanation:

The average kinetic energy can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 200 \times  {5}^{2} \\   = 100 \times 25

We have the final answer is

<h3>2500 J</h3>

Hope this helps you

5 0
3 years ago
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