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SashulF [63]
3 years ago
15

What factor from the choices below determines whether

Physics
1 answer:
Andreas93 [3]3 years ago
7 0

Answer:

a

Explanation:

Stars with very big masses will become neutron stars or black holes.

Smaller stars will become white dwarfs

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What is addictive about vaping?
AnnZ [28]
Answer:
The last one, nicotine from tobacco
4 0
3 years ago
What are the products of a fusion reaction? Check all that apply. Lighter atoms energy heavier atoms a neutron a proton.
svet-max [94.6K]

The process by which two or more tiny nuclei unite to generate a bigger nucleus is known as a nuclear fusion reaction. Heavier atoms are products of a fusion reaction.

<h3 /><h3>What is nuclear fusion?</h3>

The process by which two or more tiny nuclei unite to generate a bigger nucleus is known as a nuclear fusion reaction.

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Hence heavier atoms are e products of a fusion reaction.

To learn more about nuclear fusion refer to the link;

brainly.com/question/14019172

6 0
2 years ago
Which example best represents the use of creativity in a scientific inquiry
vova2212 [387]
From  all the options listed, as seen in the picture attached,  the example which best represents the use of creativity in a scientific inquiry is option D. i.e. <span>developing a new way to extract a particular protein from tissue samples. Figuring out new methods and implementing them is what is called as creativity in scientific inquiry.</span>

5 0
4 years ago
Read 2 more answers
Lindsay is late to class and is running down the hallway at a speed of 2 m/s the length of the hallway is 150 meters . How long
Mamont248 [21]

Explanation:

a=v-u\t

2=150-0/t

2t=150

t=75sec

7 0
3 years ago
A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of
Leto [7]

Answer: 2.27\ m/s^2

Explanation:

Given

Length of the race track L=200\ m

the radius of curvature of the track r=29.5\ m

time taken to run on track is t=24.4\ s

Speed of runner is

\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s

Centripetal acceleration is

\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2

5 0
3 years ago
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