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Oxana [17]
3 years ago
7

One problem with weight training as a way to improve overall health is that the results of a weight-training program are not mea

surable. Please select the best answer from the choices provided. T F
Physics
2 answers:
Lelu [443]3 years ago
6 0

Answer:

FALSE !!!

Explanation:

Edge 2020 ;)

Ede4ka [16]3 years ago
5 0

One problem with weight training as a way to improve overall health is that the results of a weight-training program are not measurable.

B.False

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Suppose you want to determine the resistance of a resistor that is nominally 100 . You should be able to apply 10 V across the r
Butoxors [25]

Answer:

a) For y = 102 mA, R = 98.039 ohms

For y = 97 mA, R = 103.09 ohms

b) Check explanatios for b

Explanation:

Applied voltage, V = 10 V

For the first measurement, current y_{1} = 102 mA = 0.102 A

According to ohm's law, V = IR

R = V/I

Here, I = y_{1}

R = \frac{V}{y_{1} } \\R = \frac{10}{0.102} \\R = 98.039 ohms

For the second measurement, current y_{2} = 97 mA = 0.097 A

R = \frac{V}{y_{2} }

R = \frac{10}{0.097} \\R = 103 .09 ohms

b) y = \left[\begin{array}{ccc}y_{1} &y_{2} \end{array}\right] ^{T}

y = \left[\begin{array}{ccc}y_{1} \\y_{2} \end{array}\right]

y = \left[\begin{array}{ccc}102*10^{-3} \\97*10^{-3}  \end{array}\right]

A linear equation is of the form y = Gx

The nominal value of the resistance = 100 ohms

x = \left[\begin{array}{ccc}100\end{array}\right]

\left[\begin{array}{ccc}102*10^{-3} \\97*10^{-3}  \end{array}\right] =  \left[\begin{array}{ccc}G_{1} \\G_{2}  \end{array}\right] \left[\begin{array}{ccc}100\end{array}\right]\\\left[\begin{array}{ccc}G_{1} \\G_{2}  \end{array}\right] =  \left[\begin{array}{ccc}102*10^{-5} \\97*10^{-5}  \end{array}\right]

3 0
3 years ago
A rotating space station is said to create "artificial gravity" - a loosely-defined term used for an acceleration that would be
FrozenT [24]

Answer:

\omega=0.31\frac{rad}{s}

Explanation:

The artificial gravity generated by the rotating space station is the same centripetal acceleration due to the rotational motion of the station, which is given by:

a_c=\frac{v^2}{r}(1)

Here, r is the radius and v is the tangential speed, which is given by:

v=\omega r(2)

Here \omega is the angular velocity, we replace (2) in (1):

a_c=\frac{(\omega r)^2}{r}\\\\a_c=\omega^2r

Recall that r=\frac{d}{2}=\frac{200m}{2}=100m.

Solving for \omega:

\omega=\sqrt{\frac{a_c}{r}}\\\omega=\sqrt{\frac{9.8\frac{m}{s^2}}{100m}}\\\omega=0.31\frac{rad}{s}

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The wedge and screw simple machines
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Decreasing the trains velocity will ______ the kinetic energy.<br><br> Decrease or Increase
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Decreasing the trains velocity will DECREASE the kinetic energy
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What is the longitude of the middle of romano swamp?
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