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2 years ago

An iceberg at its melting point

Physics

1 answer:

iren2701 [21]2 years ago

5 0

The mass of the iceberg is 71.9 kg

Explanation:

The amount of thermal energy needed to completely melt a substance at its melting point is given by

$Q=\lambda m$

where

$\lambda$ is the latent heat of fusion

m is the mass of the substance

In this problem, we have a block of ice at its melting point (zero degrees). The amount of heat given to the block is

$Q=2.40\cdot 10^7 J$

And the latent heat of fusion of ice is

$\lambda = 334 J/g$

So, we can re-arrange the equation to find m, the amount of ice that will melt:

$m=\frac{Q}{\lambda}=\frac{2.40\cdot 10^7}{334}=71856 g = 71.9 kg$

Learn more about specific heat:

brainly.com/question/3032746

brainly.com/question/4759369

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Please answer ASAP, and please don't joke around and actually do answer my question. I will give you brainliest if you answer it

hammer [34]

Answer:

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Explanation:

First off, if they are throwing at 12.0 m/s and it takes 2.5 seconds. It will be the act of multiplication.

12 times 2.5 is 30, because 12 times 2 is 24 plus 12 divided by 2 which is 6 so 24 plus 6 is 30.

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3 years ago

In a double slit experiment, the distance between the slits is 0.2 mm and the distance to the screen is 100 cm. What is the phas

Anni [7]

Answer:

The phase difference is $\Delta \phi = 180^o$

Explanation:

From the question we are told that

The distance between the slits is $d = 0.2 \ mm = \frac{0.2}{1000} = 0.2 *10^{-3} \ m$

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Generally the path difference of this waves is mathematically represented as

$y = d sin \theta$

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This implies that

$tan \theta = \frac{L}{D}$

=> $\theta = tan ^{-1} \frac{L}{D}$

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Substituting values into the formula for path difference

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The phase difference is mathematically represented as

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Substituting values

$\Delta \phi = \frac{2 \pi }{400 *10^{-9} } \ * 9.997*10^{-7}$

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valina [46]

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2 years ago

Consider four point charges arranged in a square with sides of length L. Three of the point charges have charge q and one of the

nydimaria [60]

Answer: $F_{net}=\frac{kq^2}{(L)^2}\left [ \frac{1}{2}+\sqrt{2}\right ]$

Explanation:

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