An iceberg at its melting point

Physics

1 answer:

iren2701 [21]3 years ago

5 0

The mass of the iceberg is 71.9 kg

Explanation:

The amount of thermal energy needed to completely melt a substance at its melting point is given by

$Q=\lambda m$

where

$\lambda$ is the latent heat of fusion

m is the mass of the substance

In this problem, we have a block of ice at its melting point (zero degrees). The amount of heat given to the block is

$Q=2.40\cdot 10^7 J$

And the latent heat of fusion of ice is

$\lambda = 334 J/g$

So, we can re-arrange the equation to find m, the amount of ice that will melt:

$m=\frac{Q}{\lambda}=\frac{2.40\cdot 10^7}{334}=71856 g = 71.9 kg$

Learn more about specific heat:

brainly.com/question/3032746

brainly.com/question/4759369

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A force of 6600 N is exerted on a piston that has an area of 0.010 m2

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Answer:

Choice A: approximately $0.015\; \rm m^2$ , assuming that the two pistons are connected via some confined liquid to form a simple machine.

Explanation:

Assume that the two pistons are connected via some liquid that is confined. Pressure from the first piston:

$\displaystyle P_1 = \frac{F_1}{A_1} = \frac{6.600\times 10^3\; \rm N}{1.0\times 10^{-2}\; \rm m^{2}} = 6.6\times 10^{5}\; \rm N \cdot m^{-2}$ .

By Pascal's Principle, because the first piston exerted a pressure of $6.6\times 10^{5}\; \rm N \cdot m^{-2}$ on the liquid, the liquid will now exert the same amount of pressure on the walls of the container.

Assume that the second piston is part of that wall. The pressure on the second piston will also be $6.6\times 10^{5}\; \rm N \cdot m^{-2}$ . In other words:

$P_2 = P_1 = 6.6\times 10^{5}\; \rm N \cdot m^{-2}$ .