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QveST [7]
1 year ago
7

Which rational number could be graphed between 0 and 1?A number line going from negative 5 to positive 3 in increments of 1.Nega

tive one-halfOne-fourthThree-halves1.75
Physics
1 answer:
vovikov84 [41]1 year ago
7 0

In order to find which rational number is between 0 and 1, let's convert them into their decimal form:

\begin{gathered} \text{negative one-half:} \\ -\frac{1}{2}=-0.5 \\  \\ \text{one}-\text{fourth:} \\ \frac{1}{4}=0.25 \\  \\ \text{three}-\text{halves:} \\ 3\cdot\frac{1}{2}=\frac{3}{2}=1.5 \\  \\ 1.75 \end{gathered}

Looking at the numbers in their decimal form, we can see that the number between 0 and 1 is one-fourth, therefore the correct option is the second one.

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A. 6.36 lbm/s

b. T_2=341\textdegree F

Explanation:

a. Given the following information;

#Compressor inlet:

Air pressure,P_1=14.7psia,T_1=60\textdegree F

#Compressor outlet:

Air \ Pressure, P_2=150psia\\\\Air \ volume \ flow \ rate, \dot V_1=5000ft^3/min

#Cooling rate,

q_{out}=10Btu/lbm, \dot W=700hp

# From table A-1E

Gas constant of air R=0.3704\ psia.ft^3/lbm.R

Specific enthalpy at P_1=520R-h_1=124.27Btu/lbm

Using the mass balance:

\dot m_{in}-\dot m_{out}=\bigtriangleup \dot m_{sys}=0.0\\\\\dot m_{in}=\dot m_{out}\\\\v_1=\frac{RT_1}{P_1}\\\\v_1=\frac{0.3704\times520}{14.7}\\\\\\v_1=13.1026ft^3/lbm\\\\\dot m=\frac{5000/60}{13.1025}\\\\\dot m=6.36\ lbm/s

Hence, the mass flow rate of the air is 6.36lbm/s

b The specific enthalpy at the exit is defined as the energy balance on the system:

\dot m_{in}-\dot m_{out}=\bigtriangleup \dot m_{sys}=0.0\\\\\dot m_{in}=\dot m_{out}\\\\\dot W_{in}+ \dot mh_1=\dot Q_{out}+\dot m_2\\\\h_2=\frac{\dot W_{in}-\dot Q_{out}}{\dot m}+h_1\\\\h_2=\frac{700\times 0.7068-10\times 6.36}{6.36}+124.27\\\\h_2=192.06\ Btu/lbm\\\\#at \ h_2=182.06Btu/lbm, T_2=801R=341\textdegree F

Hence, the temperature at the compressor exit T_2=341\textdegree F

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