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3 years ago

9

a hammer of mass 5 kg travelling at 4 metre per second is a nail directly and does not rebound what is the impulse of the hammer

1 answer:

dmitriy555 [2]3 years ago

5 0

20 kg.m/s
p =m*v = 5*4 = 20

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Which can a drop of liquid mercury can be described as?

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Option D) A drop of mercury is both a pure substance and and element.
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3 years ago

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2. What will be the extension of this spring if the load is a) 4N and b) 75 g?

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3 years ago

A mixture of nitrogen and xenon gases, at a total pressure of 836 mm Hg, contains 2.80 grams of nitrogen and 24.9 grams of xenon

larisa86 [58]

Answer: Partial pressure of nitrogen and xenon are 288mmHg and 548 mmHg respectively.

Explanation:

The partial pressure of a gas is given by Raoult's law, which is:

$p_A=p_T\times \chi_A$

where,

$p_A$ = partial pressure of substance A

$p_T$ = total pressure

$\chi_A$ = mole fraction of substance A

We are given:

$m_{N_2}=2.80g$

$m_{Xe}=24.9g$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

And,

$n_A=\frac{m_A}{M_A}$

Mole fraction of nitrogen is given as:

$\chi_{N_2}=\frac{\frac{m_{N_2}}{M_{N_2}}}{(\frac{m_{N_2}}{M_{N_2}}+\frac{m_{Xe}}{M_{Xe}})}$

Molar mass of $N_2$ = 28 g/mol

Molar mass of $Xe$ = g/mol

Putting values in above equation, we get:

$\chi_{N_2}=\frac{\frac{2.80}{28}}{\frac{2.80}{28}+\frac{24.9}{131}}$

$\chi_{N_2}=\frac{0.100}{0.100+0.190}=0.345$

To calculate the mole fraction of xenon, we use the equation:

$\chi_{Xe}+\chi_{N_2}=1\\\\\chi_{Xe}=1-0.345=0.655$

$p_{N_2}=836mmHg\times 0.345=288mmHg$

$p_{Xe}=836mmHg\times 0.655=548mmHg$

Thus partial pressure of nitrogen and xenon are 288mmHg and 548 mmHg respectively.

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3 years ago

If the total momentum for a system is the same before and after the collision, we say that momentum is conserved. If momentum we

andrew-mc [135]

Answer:

Ratio = 1:1

Explanation:

$P_{i}$ = initial momentum of the system

$P_{f}$ = final momentum of the system

For the momentum to be conserved , final total momentum must be equal to initial total momentum, so we have

$P_{f} = P_{i}$

Dividing both side by $P_{i}$ , we get

$\frac{P_{f}}{P_{i}} = \frac{P_{i}}{P_{i}} \\\frac{P_{f}}{P_{i}} = 1\\$

hence

Ratio = 1

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Which atom is invloved in giving your heart energy to beat ?

Juli2301 [7.4K]

Answer:

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Explanation:

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