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Dennis_Churaev [7]
3 years ago
8

. A storm sewer is carrying snow melt containing 1.200 g/L of sodium chloride into a small stream. The stream has a naturally oc

curring sodium chloride concentration of 20 mg/L. If the storm sewer flow rate is 2,000 L/min and the stream flow rate is 2.0 m3 /s, what is the concentration of salt in the stream after the discharge point? Assume that the sewer flow and the stream flow are completely mixed, that the salt is a conservative substance (it does not react), and that the system is at steady state.
Engineering
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

Explanation:

In the steady state total volume going out will be equal to total volume coming in , and

total salt coming in = total salt going out

Total volume coming in per minute = 2000 + 2 x 10³ x 60

= 122000 L .

Total salt coming in per minute = 1200 x 2000 + 20  x 2 x 10³ x 60

= 2400000 + 2400000 mg

= 4800000 mg

volume of water going out per minute = 122000 L

Total salt going out  per minute = 4800000 mg

concentration of water going out = 4800000 / 122000

= 39.344 mg / L

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Consider a W21x93. Determine the moment capacity of the beam. Assume the compression flange is not laterally braced and that the
OLga [1]

Answer:

The answer is "828.75"

Explanation:

Please find the correct question:

For W21x93 BEAM,

Z_x = 221.00 in^3 \\\\\to \frac{b_t}{2t_f} =4.53\\\\\to \frac{h}{t_w}=32.3

For A992 STREL,

F_y= 50\  ks

Check for complete section:

\to \frac{b_t}{2t_f} =4.53 < \frac{65}{\sqrt{f_y = 9.19}}\\\\\to \frac{h}{t_w} =32.3 < \frac{640}{\sqrt{f_y = 90.5}}

Design the strength of beam =\phi_b Z_x F_y\\\\

                                                =0.9 \times 221 \times 50\\\\=9945 \ in \ \ kips\\\\=\frac{9945}{12}\\\\= 828.75 \ft \ kips \\

8 0
3 years ago
For this question you must write a java class called Rectangle and a client class called RectangleClient. The partial Rectangle
Alex Ar [27]

Answer:

Java program is given below. You can get .class after you execute java programs, You can attach those files along with .java classes given , Those .class files are generated ones.

Explanation:

//Rectangle.java class

public class Rectangle {

private int x;

private int y;

private int width;

private int height;

// constructs a new Rectangle with the given x,y, width, and height

public Rectangle(int x, int y, int w, int h)

{

this.x=x;

this.y=y;

this.width=w;

this.height=h;

}

// returns the fields' values

public int getX()

{

return x;

}

public int getY()

{

return y;

}

public int getWidth()

{

return width;

}

public int getHeight()

{

return height;

}

// returns a string such as “Coordinate is (5,12) and dimension is 4x8” where 4 is width and 8 is height. public String toString()

public String toString()

{

String str="";

//add x coordidate , y-coordinate , width, height and area to str and return

str+="Coordinate is ("+x+","+y+")";

str+=" and dimension is : "+width+"x"+height;

str+=" Area is "+(width*height);

return str;

}

public void changeSize(int w,int h)

{

width=w;

height=h;

}

}

======================

//main.java

class Main {

public static void main(String[] args) {

//System.out.println("Hello world!");

//create an object of class Rectangle

Rectangle rect=new Rectangle(5,12,4,8);

//print info of rect using toString method

System.out.println(rect.toString());

//chamge width and height

rect.changeSize(3,10);

//print info of rect using toString method

System.out.println(rect.toString());

}

}

==========================================================================================

//Output

Coordinate is (5,12) and dimension is : 4x8 Area is 32

Coordinate is (5,12) and dimension is : 3x10 Area is 30

========================================================================================

6 0
3 years ago
How long...you...novels? A. Have/write B. Do/write C. Have/written D. Did/go
soldi70 [24.7K]

Answer:

Answer is B.

Explanation:

Subject verb agreement

3 0
3 years ago
Read 2 more answers
Patient people vote more often than non-patient people.<br> True<br> O<br> False
xxMikexx [17]

Answer:

True

Explanation:

8 0
3 years ago
In a voltage-divider biased pnp transistor, there is no base current, but the base voltage is approximately correct. The most li
N76 [4]

Answer:

the base-emitter junction is open and the emitter resistor is open

Explanation:

Because here there will be no base current only when the the base emitter junction is kept open and. Also when emitter resistor is kept open or with thus there will be no voltage drop across the Resistor meaning the base voltage Will be equal to that in the voltage divider circuitry

4 0
3 years ago
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