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Dennis_Churaev [7]
3 years ago
8

. A storm sewer is carrying snow melt containing 1.200 g/L of sodium chloride into a small stream. The stream has a naturally oc

curring sodium chloride concentration of 20 mg/L. If the storm sewer flow rate is 2,000 L/min and the stream flow rate is 2.0 m3 /s, what is the concentration of salt in the stream after the discharge point? Assume that the sewer flow and the stream flow are completely mixed, that the salt is a conservative substance (it does not react), and that the system is at steady state.
Engineering
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

Explanation:

In the steady state total volume going out will be equal to total volume coming in , and

total salt coming in = total salt going out

Total volume coming in per minute = 2000 + 2 x 10³ x 60

= 122000 L .

Total salt coming in per minute = 1200 x 2000 + 20  x 2 x 10³ x 60

= 2400000 + 2400000 mg

= 4800000 mg

volume of water going out per minute = 122000 L

Total salt going out  per minute = 4800000 mg

concentration of water going out = 4800000 / 122000

= 39.344 mg / L

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Answer:

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Explanation:

Given data:

flow rate = 10 gallon per  minute = 0.0223 ft^3/sec

diameter = 0.75 inch

we know discharge is given as

Q =  VA

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V = \frac{0.223}{\frac{\pi}{4} \frac{0.75}{12}}

V = 7.27 ft/sec

we know that Reynold number

Re = \frac{VD}{\nu}

Re = \frac{7.27 \times \frac{0.75}{12}}{1.21\times 10^{-5}}

Re = 3.76 \times 10^4

calculate the \frac{\epsilon }{D}ratio to determine the fanning friction f

\frac{\epsilon }{D} = \frac{0.0005}{\frac{0.75}{12}} = 0.008

from moody diagram f value corresonding to Re and \frac{\epsilon }{D}is 0.037

for horizontal pipe

\delta p = \frac{f l \rho v^2}{2D}

\frac{\delta p }{l} = \frac{1 \times 0.037 \times 1.94 \times 7.27}{\frac{0.75}{12}}

where 1.94 slug/ft^3is density of  water

\frac{\delta p }{l} = 30.4 lb/ft^3

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3 years ago
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In order to avoid a rollover, what is the highest degree incline one should mow on? 10-degree incline 5-degree incline 30-degree
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What is flow energy? Do fluids at rest possess any flow energy?
anzhelika [568]

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3 years ago
A cylindrical insulation for a steam pipe has an inside radius rt = 6 cm, outside radius r0 = 8 cm, and a thermal conductivity k
goldfiish [28.3K]

Answer:

heat loss per 1-m length of this insulation is 4368.145 W

Explanation:

given data

inside radius r1 = 6 cm

outside radius r2 = 8 cm

thermal conductivity k = 0.5 W/m°C

inside temperature t1 = 430°C

outside temperature t2 = 30°C

to find out

Determine the heat loss per 1-m length of this insulation

solution

we know thermal resistance formula for cylinder that is express as

Rth = \frac{ln\frac{r2}{r1}}{2 \pi *k * L}   .................1

here r1 is inside radius and r2 is outside radius L is length and k is thermal conductivity

so

heat loss is change in temperature divide thermal resistance

Q = \frac{t1- t2}{\frac{ln\frac{r2}{r1}}{2 \pi *k * L}}

Q = \frac{(430-30)*(2 \pi * 0.5 * 1}{ln\frac{8}{6} }

Q = 4368.145 W

so heat loss per 1-m length of this insulation is 4368.145 W

4 0
3 years ago
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