Economic cost is a rescission making tangible factor true
Answer:
hello some data related to your question is missing attached below is the missing data
answer : 63700 Ib/hr
Explanation:
Given data :
Limestone mix : consists of 94% CaCO3 and 6% inert material
Actual feed rate = 36,000 Ib/hr
SO2 in flue gas = 20,314 Ib/hr
FGD efficiency = 97%
resulting sludge contains 58% solids
<u>Calculate the Total sludge production rate </u>
First : determine SO2 removed in sludge
= 0.97 * 20314
= 19704.58 Ib/hr
next : moles of SO2 removed
= 19704.58 / 64 Ib/ Ib mol
= 307.88 Ib mol / hr
also moles of CaSO3 produced = 307.88 Ib mol / hr
mass of CaSO3 = 307.88 * 120 = 36946.09 Ib/hr
Therefore Total sludge production rate
= 36946.09 / 0.58
= 63700.15 Ib/hr
<u />
<u />
<u />
<u />
Answer:
0.064 mg/kg/day
6.25% from water, 93.75% from fish
Explanation:
Density of water is 1 kg/L, so the concentration of the chemical in the water is 0.1 mg/kg.
The BCF = 10³, so the concentration of the chemical in the fish is:
10³ = x / (0.1 mg/kg)
x = 100 mg/kg
For 2 L of water and 30 g of fish:
2 kg × 0.1 mg/kg = 0.2 mg
0.030 kg × 100 mg/kg = 3 mg
The total daily intake is 3.2 mg. Divided by the woman's mass of 50 kg, the dosage is:
(3.2 mg/day) / (50 kg) = 0.064 mg/kg/day
b) The percent from the water is:
0.2 mg / 3.2 mg = 6.25%
And the percent from the fish is:
3 mg / 3.2 mg = 93.75%
Answer:
Inspectors use inductive reasoning on the job.
Explanation:
I just took the test.