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3 years ago

9

Technician A says diesel engines are also called compression ignition engines. Technician B says diesel engines have much higher

compression ratios. Who is correct

1 answer:

konstantin123 [22]3 years ago

3 0

Answer:

Both Technician A and Technician B

Explanation: Both technicians are correct.

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A window‐mounted air‐conditioning unit (AC) removes energy by heat transfer from a room, and rejects energy by heat transfer to

Arada [10]

Solution :

Given :

The power of the air‐conditioning (AC) unit is , W = 0.434 kW

The coefficient of performance or the COP of the air‐conditioning (AC) unit is given by = 6.22

Therefore he heat removed is given by , $Q_H = 6.22 \times 0.434$

$Q_H = 2.7 \ kW$

Now if the electricity is valued at 0.10 dollar per kW hour, then the operating cost of the air conditioning unit in 24 hours is given by = 0.10 x 2.7 x 24

= 6.48

Therefore the operating cost = $ 6.48 for 24 hours.

3 0

3 years ago

When you see a street with white markings only, what kind of street is it?

Georgia [21]

Answer:

it's a one way street

3 0

4 years ago

2–25 Consider a medium in which the heat conduction equation is given in its simplest form as

barxatty [35]

Answer:

d) Is the thermal conductivity of the medium constant or variable.

Explanation:

As we know that

Heat equation with heat generation at unsteady state and with constant thermal conductivity given as

$\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}+\dfrac{\dot{q}_g}{K}=\dfrac{1}{\alpha }\dfrac{dT}{dt}$

With out heat generation

$\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}$

In 2 -D with out heat generation with constant thermal conductivity

$\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}$

Given equation

$\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{a }\dfrac{dT}{dt}$

So we can say that this is the case of with out heat generation ,unsteady state and with constant thermal conductivity.

So the option d is correct.

d) Is the thermal conductivity of the medium constant or variable.

3 0

3 years ago

To determine if a product or substance being used is hazardous, consult:__________.

qwelly [4]

Answer:

Option B: An MSDS

Explanation:

A dictionary is used to check up the meaning of general words and not for checking if a substance being used is hazardous. Option A is wrong.

MSDS means "Material Safety Data Sheet" and it contains documents with information that relates to occupational health & safety for checking various substances and products. Thus, option B is correct.

SAE stands for Society of Automotive Engineering and their standards pertain to mainly Automobiles. Thus option C is wrong.

EPA guidelines are mainly for checking facility and environmental health and safety compliance. Thus, option D is wrong.

3 0

4 years ago

A sheet of steel 2.5 mm thick has nitrogen atmosphere on both sides at 900 oC and is permitted to achieve a steady-state diffusi

DanielleElmas [232]

Answer:

1.8 mm

Explanation:

given data

thick = 2.5 mm

flux = 1 × $10^{-7}$ kg/m²

high pressure surface is 2 kg/m³

solution

we use fick first law for steady state diffusion

J = D × $\frac{Ca - Cb}{Xa - Xb}$ ..........1

we take here Ca to point which concentration of nitrogen is 2 kg/m³

so we solve Xb

Xb = Xa + D × $\frac{Ca - Cb}{J}$

assume Xa = 0 at surface

Xb = 0 + ( 12 × $10^{-11}$ ) × $\frac{2 - 0.5}{1*10^{-7}}$

Xb = 1.8 × $10^{-3}$

Xb = 1.8 mm

8 0

3 years ago