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alukav5142 [94]
3 years ago
8

In the figure, WY¯¯¯¯¯¯¯¯¯WY¯ and XZ¯¯¯¯¯¯¯¯XZ¯ intersect at point VV, the measure of ∠WVZ∠WVZ is (11x−19)°(11x−19)°, and the me

asure of ∠WVX∠WVX is (8x+28)°(8x+28)°.
What is the measure of ∠YVZ∠YVZ?
Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0
Assuming a diagram similar to the one I've attached, ∠<em>YVZ</em> is a vertical angle to ∠<em>WVX</em>, which means they have an equal measure.  Additionally, ∠<em>WVZ</em> and ∠<em>WVX</em> form a linear pair, which means they are supplementary (sum to 180°).  That means we start out with the equation
(11x-19)+(8x+28)=180
We combine our like terms (the <em>x</em>'s get combined, then the constants get combined) and have:
19x+9=180
Cancel the 9 first by subtraction:
19x+9-9=180-9 \\ 19x=171
Cancel the 19 by division:
\frac{19x}{19}= \frac{171}{19}   \\ x=9
Since we know that our angle we're looking for, ∠<em>YVZ</em>, is the same measure as ∠<em>WVX</em>, we substitute 9 in for <em>x</em>:
8(9)+28=72+28=100°
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