Answer:
a) X[bar]₁= 1839.20 cal
b) X[bar]₂= 1779.07 cal
c) S₁= 386.35 cal
Step-by-step explanation:
Hello!
You have two independent samples,
Sample 1: n₁= 15 children that did not eat fast food.
Sample 2: n₂= 15 children that ate fast food.
The study variables are:
X₁: Calorie consumption of a kid that does not eat fast food in one day.
X₂: Calorie consumprion of a kid that eats fast food in one day.
a)
The point estimate of the population mean is the sample mean
X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal
b)
X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal
c)
To calculate the sample standard deiation, you have to calculate the sample variance first:
S₁²= 
[∑X₁² - (( ∑X₁)²/n₁)]= 
= 149263.4571 cal²
S₁= 386.35 cal
I hope it helps!
Step-by-step explanation:
last week there were
62 + 60 + 2 = 124 customers.
that means that the fraction of the customers, who paid by credit card, was
2/124 = 1/62
in situations like that, when we use history data and try to predict future behavior, we use that past experience and extrapolate to a predicted result.
we simply say that we expect the same fraction, 1/62, if customers to use credit cards.
for the absolute number of predicted credit card customers we multiply the predicted number of customers by the expected fraction
1000 × 1/62 = 500/31 = 16.12903226... ≈ 16
so, he expects 16 credit card customers.
Answer:
600 is closest to the actual answer so pick that.
Answer:
She sent 120 emails this month.
Step-by-step explanation:
Multiply 200 by .60 (60 percent) and it will give you 120.
I used 60 instead of 40 because the problem said 40 percent less, NOT 40 percent of 200.
