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mixer [17]
3 years ago
7

At the beginning of an experiment, a scientist has 356 grams of radioactive goo. After 210 minutes, her sample has decayed to 44

.5 grams. Find a formula for G ( t ) , the amount of goo remaining at time t . Keep at least 5 decimal places.
Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:  \bold{G(t)=356e^{-0.59413t}}

<u>Step-by-step explanation:</u>

Use the decay formula: P=P_oe^{kt}   where

  • P is the remaining amount of the sample
  • P₀ is the original amount of the sample
  • k is the decay rate
  • t is the time (in hours)

Given: P = 44.5, P₀ = 356, k = unknown, t = 210 minutes (3.5 hours)

44.5=356e^{k(3.5)}\\\\\\\dfrac{44.5}{356}=e^{3.5k}\\\\\\0.125=e^{3.5k}\\\\\\ln(0.125)=3.5k\\\\\\\dfrac{ln(0.125)}{3.5}=k\\\\\\-0.59413=k

Input P₀ = 356 and k = -0.59413 into the decay formula

              \large\boxed{P=356e^{-0.59413t}}

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Solve for the value of k
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Answer:

From the question we are told that

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    The sample size is  n  =  30  

     The  sample mean is  \= x =  16.32

     The  population standard deviation is  \sigma  =  0.8

      The  level of significance is  \alpha  = 0.10

Step 1: State hypotheses:

The  null hypothesis is  H_o :  \mu = 16

The alternative hypothesis is  H_a :  \mu \ne  16

Step 2: State the test statistic. Since we know the population standard deviation and the sample is large our test statistics is

          t = \frac{ \= x  -\mu }{ \frac{\sigma}{ \sqrt{n} } }

=>       t = \frac{ 16.32  -16  }{ \frac{0.8 }{ \sqrt{30} } }

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Step 3: State the critical region(s):

From the student t-distribution table the critical value corresponding to  \alpha  = 0.10  is

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Generally the critical regions is mathematically represented as  

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Step 4: Conduct the experiment/study:

Generally the from the value obtained we see that the t value is outside the critical region so  the decision is [Reject the null hypothesis ]  

Step 5: Reach conclusions and state in English:

  There is  sufficient evidence to show that the filling weight has to be adjusted

Step 6: Calculate the p-value associated with this test. How does this the p-value support your conclusions in Step 5?

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Generally  looking at the value obtained we see that p- value <  \alpha hence

The decision rule is

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Step-by-step explanation:

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