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3 years ago

Refer to the invertebrate cladogram above to answer the following questions.

Biology

2 answers:

djyliett [7]3 years ago

4 0

Answer: They are all good

Explanation:

Alex787 [66]3 years ago

3 0

1. Multicellular
2. Multicellular, tissues, bilateral symmetry, body cavity, coelom, segmentation, jointed appendages, exoskeleton
3. Annelids
4.Jointed appendages, exoskeleton
5. Evolutionary phylogeny is unknown, but it is known to have some of these adaptive traits (multicellular, tissues, bilateral sym, body cavities, coelom)
6.sponges, jellyfish, roundworms, snails

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Glaciers pick up large rocks and carry them away. This is called _____.

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Cutting down forests changes the populations of more than trees. Imagine the organisms that lived in this forest. After the tree

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Answer:

Food and shelter are the most likely limiting factors in this case.

Explanation:

In a forest, the huge trees act as a source of shelter for the animals that live in that habitat. It protects the animals from the heat of the Sun and extreme cold conditions.

The tress in the forest are the primary source of food for almost all the organisms that live in the forest. Cutting down trees will lead to food scarcity for the animals which inhabit that forest. As a result, the animals will either have to migrate or they will become die due to lack of food.

Hence, food and shelter are the limiting factors in this case.

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The climate and features of the Earth change over time.

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Most coastal areas on Earth experience two high tides and two low tides every lunar day. What is a lunar day? Our days on Earth

ahrayia [7]

The correct answer is - C) 5:35 PM Friday.

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Since the lunar day lasts for 24 h 50 m, we should just divide it in two, thus get 12 h 25 m. Than we should add the 12 h 25 to the time when one of the low tides appeared, which is 5:10 AM, so we will get 5:35 PM.

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3 years ago

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2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago