Answer:
197.5072.
Explanation:
According to the Coulomb's law, the magnitude of the electrostatic force of interaction between two charges
and
which are separated by the distance
is given by

<em>where,</em> k is the Coulomb's constant.
For the case, when,
Then, using Coulomb's law,

For the case, when,
Then, using Coulomb's law, the new electric force between the charges is given by,

the see-saw, and the catapult.
Answer:
1.25 m
0.5 s
Explanation:
Given:
v₀ = 5 m/s
v = 0 m/s
a = -10 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (5 m/s)² + 2 (-10 m/s²) Δy
Δy = 1.25 m
Find: t
v = at + v₀
(0 m/s) = (-10 m/s²) t + (5 m/s)
t = 0.5 s