Answer:
(a) Length =136.58 m
(b) T=5995 N
Explanation:
for the glider in the back
T - 1900 = 700 a
for the glider in front
12000-T -1900 = 700a
add equations
12000-3800 = 1400 a
a=5.85 m/s^2
v^2 = v0^2 + 2 a x
40^2 = 2*5.85*x
Length =136.58 m
b) plug the a back into one of the previous formula
T - 1900 = 700*5.85
T=5995 N
The problem states that the distance travelled (d) is
directly proportional to the square of time (t^2), therefore we can write this in
the form of:
d = k t^2
where k is the constant of proportionality in furlongs /
s^2
<span>Using the 1st condition where d = 2 furlongs, t
= 2 s, we calculate for the value of k:</span>
2 = k (2)^2
k = 2 / 4
k = 0.5 furlongs / s^2
The equation becomes:
d = 0.5 t^2
Now solving for d when t = 4:
d = 0.5 (4)^2
d = 0.5 * 16
<span>d = 8 furlongs</span>
<span>
</span>
<span>It traveled 8 furlongs for the first 4.0 seconds.</span>
The motivation behind why the vertical stature of the stairs is the main thing measured is that it uncovers to us how much gravity is up against the individual and their weight, so we require this data to decide how much vitality and power we have to get up the stairs.
Answer:
13.1 m/s
Explanation:
Given that a baseball is tossed up into the air at an initial velocity 18 m/s. The height of the baseball at time t in seconds is given by h(t) = 18t−4.9t 2 (in meters).
a) What is the average velocity for [1,1.5]?
To calculate the velocity travelled by the ball, differentiate the function.
dh/dt = 18 - 9.8t
Substitute t for 1 in the above Differential function
dh/dt = 18 - 9.8 (1)
But dh/dt = velocity
V = 18 - 9.8
V = 8.2 m/s
Average velocity = ( U + V ) / 2
Average velocity = (18 + 8.2)/2
Average velocity = 26.2/2
Average velocity = 13.1 m/s
