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Korvikt [17]
3 years ago
5

What is occurring when two waves traveling along the same medium meet and cancel each other out?

Physics
2 answers:
timofeeve [1]3 years ago
6 0

Answer:

Destructive interference

Explanation:

Destructive interference occurs when waves come together in such a way that they completely cancel each other out. When two waves interfere destructively, they must have the same amplitude in opposite directions.

almond37 [142]3 years ago
6 0

Answer:

Destructive interference

Explanation:

Destructive interference occurs when waves come together in such a way that they completely cancel each other out. When two waves interfere destructively, they must have the same amplitude in opposite directions.

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An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance o
Minchanka [31]

Answer:

B. 0.16 m

Explanation:

The vertical distance by which the player will miss the target is equal to the vertical distance covered by the dart during its motion.

Since the dart is thrown horizontally, the initial vertical velocity is zero:

v_y = 0

While the horizontal velocity is

v_x = 15 m/s

The horizontal distance covered is

d_x = 2.7 m

Since the dart moves by uniform motion along the horizontal direction, the time it takes for covering this distance is

t=\frac{d_x}{v_x}=\frac{2.7 m}{15 m/s}=0.18 s

along the vertical direction, the motion is a uniformly accelerated motion with constant downward acceleration g=9.8 m/s^2, so the vertical distance covered is given by

d_y = \frac{1}{2}gt^2=\frac{1}{2}(9.8 m/s^)(0.18 s)^2=0.16 m

8 0
3 years ago
an 11 kg tool box is floating stationary in an orbiting spacecraft when a 79 kg astronaut, initially at rest, gives the tool box
snow_tiger [21]

The astronaut final velocity is 0.06 m/s to the right

Explanation:

In absence of external forces, the total momentum of the box-astronaut system is conserved.

At the beginnig, the total momentum of the two is zero, since they are at rest:

p_i = 0

While the final momentum, after the astronaut throws the box, is:

p_f=mv+MV

where

m = 11 kg is the mass of the box

M = 79 kg is the mass of the astronaut

v = -0.45 m/s (to the left) is the velocity of the box (we take left as negative direction)

V is the final velocity of the astronaut

The total momentum is conserved, so

p_i = p_f\\0=mv+MV

And solving , we find V:

V=-\frac{mv}{M}=-\frac{(11)(-0.45)}{79}=0.06 m/s

And the positive sign indicates that the direction is to the right.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

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brainly.com/question/9484203

#LearnwithBrainly

6 0
3 years ago
Suppose that a person riding on the top of a freight car shines a searchlight beam in the direction in which the train is travel
Snezhnost [94]

Answer:

same

Explanation:

Acc. to Einstien's postulate of special theory of

Relativity , Velocity of the light beam is same in all frames of references

(a) If the freight car is at rest

The frame we can assumed as Non - inertial frame  of reference s

In the inertial frame of reference , velocity  of the light beam  has its own value as : 3 x 10^8 m/s

(b) If the freight car is moving , the frame we can assumed as  Non -inertial frame of reference    

In thus case also , The velocity of the light beam  will also have  the same value as ; 3 x 108 m/s

6 0
3 years ago
New 5G networks utilize millimeter-wave radiation. Millimeter-wave radiation refers to electromagnetic waves with frequencies in
seraphim [82]

Answer:

It corresponds to 1mm-10 mm range.

Explanation:

  • Electromagnetic waves (such as the millimeter-wave radiation) travel at the speed of light, which is 3*10⁸ m/s in free space.
  • As in any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:

        v = \lambda * f  (1)

  • Replacing v= c=3*10⁸ m/s, and the extreme values of f (which are givens), in (1) and solving for λ, we can get the free-space wavelengths that correspond to the 30-300 GHz range, as follows:

       \lambda_{low} = \frac{c}{f_{high}}  = \frac{3e8m/s}{300e9Hz} = 1 mm (2)

      \lambda_{high} = \frac{c}{f_{low}}  = \frac{3e8m/s}{30e9Hz} = 10 mm (3)

4 0
2 years ago
A flow of electric charge in a wire normally requires a _________.
just olya [345]
Flow of electric charge in a wire requires " ELECTRONS "
6 0
3 years ago
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