A skier weighing 86.2 kg starts from rest and slides down a 32.0-m frictionless slope that is inclined at an angle of 15.0° with
the horizontal. Ignore air resistance.
a. calculate the work done by gravity on the skier.
b.calculate the work done by the normal force on the skier
a. calculate the work done by gravity on the skier.
b.calculate the work done by the normal force on the skier
1 answer:
Answer:
A. = 26.11kJ
B = 0N
Explanation:
Mass = 86.2kg
Distance (s) = 32m
Angle of the slope = 15°
a. Work done due to gravity
W = force * distance * angle of displacement
W = F * S * cos θ
Force = mass * acceleration due to gravity
Force = 86.2 * 9.8
Force = 844.76N
Work = 844.76 * 32 * cos 15
Work = 26111.21J
Work = 26.11kJ
b. The workdone by the normal force is equal to zero since the normal force is perpendicular to the displacement.
Hence the normal force does not act on the body.
N = 0N
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Answer:
0.075 T
Explanation:
When a current-carrying wire is immersed in a region with magnetic field, the wire experiences a force, given by
where
I is the current in the wire
L is the length of the wire
B is the strength of the magnetic field
is the angle between the direction of I and B
In this problem we have:
L = 0.65 m is the length of the wire
I = 8.2 A is the current in the wire
F = 0.40 N is the force experienced by the wire
since the current is at right angle with the magnetic field
Solving the formula for B, we find the strength of the magnetic field: