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3 years ago

2x^2+15x+2=0 Need the answers for the two x's that are equal to 0

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

6 0

Answer:

x = -2

Step-by-step explanation:

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you and your mom enter a drawing with 3 different prizes. a total of 10 people entered the drawing, and prizes are awarded rando

Serggg [28]

Answer:

The correct option is A.

Step-by-step explanation:

Number of people who entered the drawing = 10

Number of prizes = 3

Number of ways to award the prize = 720 ways

The total number of ways that 3 prizes can be awarded to the 10 people can be determined as:

10*9*8 = 720

The total number of ways in which I win the first prize and my mom wins the second prize would be 1*1*8 = 8

Thus the probability that i win the first prize and my mom wins the second prize would be 8/720 ....

5 0

3 years ago

Name the property used in n + 0 = 7.

Yanka [14]

The answer is additive property

7 0

4 years ago

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7/12 of a new dress has been sewn Chelsea did 3/7 of the sewing how much of the dress did Chelsea sew

KiRa [710]

Answer:

1/4

Step-by-step explanation:

7/12 X 3/7 = 21/84 = 1/4

6 0

3 years ago

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1. What is the solution of n² – 49 = 0? (1 point)

maks197457 [2]

Answer:

1. $n=\pm7$

2. $x=\pm7i[tex]3.[tex]\pm 12x =a$

4. 22

Step-by-step explanation:

1. $n^2 - 49 = 0$

$n^2 =49$

$n= \sqrt{49}$

$n=\pm7$

2. $x^2+64 = 0$

$x^2 =-64$

$x= \sqrt{49}$

$x=\pm7i[tex]3. Area of square = [tex]a^{2}$

Where a is the side

We are given an area o square = $144x^{2}$

So, $144x^{2}=a^{2}$

$\sqrt{144x^{2}}=a$

$\pm 12x =a$

4. We are given that the solution of quadratic equation -9 and 9

So, equation becomes:

$(x+9)(x-9)=0$

$x^2- 81=0$

So, in the given equation $x^2 + z = 103$

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

$x^2 + 22 = 103$

$x^2 + 22 -103=0$

$x^2 -81=0$

Thus the value of z is 22

8 0

3 years ago

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Write the equation of the line passing through the point (-2; 2) that is

Brut [27]

Answer:

2y-x-6=0

Step-by-step explanation:

6 0

3 years ago